从spring MVC控制器返回xml文件

问题描述

我已经尝试了很多从控制器函数返回文件。

I have tried a lot to return a file from the controller function.

这是我的功能：

@RequestMapping(value = "/files", method = RequestMethod.GET)
@ResponseBody public FileSystemResource getFile() {
     return new FileSystemResource(new File("try.txt"));
}

我收到此错误消息：

有没有人知道如何解决它？

Does anyone have an idea how to solve it?

而且，我应该如何从客户端发送（JavaScript，jQuery）？

And, how should I send from the client (JavaScript, jQuery)?

推荐答案

编辑2：首先 - 参见底部的编辑1 - 这是正确的方法。但是，如果您无法使序列化程序工作，您可以使用此解决方案，将XML文件读入字符串，并促使用户保存它：

EDIT 2: First of all - see edit 1 in the bottom - that't the right way to do it. However, if you can't get your serializer to work, you can use this solution, where you read the XML file into a string, and promts the user to save it:

@RequestMapping(value = "/files", method = RequestMethod.GET)
public void saveTxtFile(HttpServletResponse response) throws IOException {

    String yourXmlFileInAString;
    response.setContentType("application/xml");
    response.setHeader("Content-Disposition", "attachment;filename=thisIsTheFileName.xml");

    BufferedReader br = new BufferedReader(new FileReader(new File(YourFile.xml)));
    String line;
    StringBuilder sb = new StringBuilder();

    while((line=br.readLine())!= null){
        sb.append(line);
    }

    yourXmlFileInAString  = sb.toString();

    ServletOutputStream outStream = response.getOutputStream();
    outStream.println(yourXmlFileInAString);
    outStream.flush();
    outStream.close();
}

这应该可以胜任。但请记住，浏览器会缓存网址内容 - 因此每个文件使用唯一的网址可能是个好主意。

That should do the job. Remember, however, that the browser caches URL contents - so it might be a good idea to use a unique URL per file.

编辑：

经过进一步检查后，您还应该能够将以下代码添加到您的操作中，以使其正常工作：

After further examination, you should also just be able to add the following piece of code to your Action, to make it work:

response.setContentType("text/plain");

（或者对于XML）

response.setContentType("application/xml");

所以你的完整解决方案应该是：

So your complete solution should be:

@RequestMapping(value = "/files", method = RequestMethod.GET)
@ResponseBody public FileSystemResource getFile(HttpServletResponse response) {
    response.setContentType("application/xml");
    return new FileSystemResource(new File("try.xml")); //Or path to your file
}

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