问题描述
我正在使用 jQuery 的 $.getJSON()
对我的简单 Spring MVC 后端进行异步调用.大多数 Spring 控制器方法如下所示:
I am using jQuery's $.getJSON()
to make asynchronous calls to my simple Spring MVC backend. Most of the Spring controller methods look like this:
@RequestMapping(value = "/someURL", method = RequestMethod.POST)
public @ResponseBody SomePOJO getSomeData(@ModelAttribute Widget widget,
@RequestParam("type") String type) {
return someDAO.getSomeData(widget, type);
}
我设置了一些东西,以便每个控制器以 JSON 形式返回 @ResponseBody
,这是客户端所期望的.
I have things set up so that each controller returns the @ResponseBody
as JSON, which is what the client-side expects.
但是当请求不应该向客户端返回任何内容时会发生什么?我可以吗:
But what happens when a request isn't supposed to return any content to the client-side? Can I have:
@RequestMapping(value = "/updateSomeData" method = RequestMethod.POST)
public @ResponseBody void updateDataThatDoesntRequireClientToBeNotified(...) {
...
}
如果不是,这里使用的适当语法是什么?
If not, what's the appropriate syntax to use here?
推荐答案
你可以返回void,然后你必须用@ResponseStatus(value = HttpStatus.OK) 标记方法你不需要@ResponseBody
you can return void, then you have to mark the method with @ResponseStatus(value = HttpStatus.OK) you don't need @ResponseBody
@RequestMapping(value = "/updateSomeData" method = RequestMethod.POST)
@ResponseStatus(value = HttpStatus.OK)
public void updateDataThatDoesntRequireClientToBeNotified(...) {
...
}
只有 get 方法隐式返回 200 状态代码,所有其他方法都执行以下三件事之一:
Only get methods return a 200 status code implicity, all others you have do one of three things:
- 返回void并用
@ResponseStatus(value = HttpStatus.OK)
标记方法 - 返回一个对象并用
@ResponseBody
标记它 - 返回一个
HttpEntity
实例
- Return void and mark the method with
@ResponseStatus(value = HttpStatus.OK)
- Return An object and mark it with
@ResponseBody
- Return an
HttpEntity
instance
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