问题描述
我需要我的控制器返回一个AJAX JSON响应包含更新的HTML code。
I need my controller to return an AJAX JSON response that contains the updated HTML code.
更新HTML code是通过渲染一个JSP视图中创建。
The updated HTML code is created by rendering a JSP view.
例如：JSP：
<tr>
<td>${data1}</td>
<td>${data2}</td>
</tr>
JSON响应：
JSON response:
{"columns" : "2", "rows":"1", "data":rendered view}
目前我试图创建一个我自己的OutputStream一个虚拟的响应，并把在JSON响应渲染视图的内容，但没有运气。
Currently I'm trying to create a dummy response with "my own" outputstream and put the rendered view content in the json response, but with no luck.
除了事实，我不能让这个解决方案的工作，它不适合我。用正确的方法任何提示做呢？
Other than the fact I can't get this solution to work, it doesn't feel right.Any tips on the proper way to do it?
谢谢，大利
推荐答案
如果你想捕捉的看法是 /WEB-INF/views/my.jsp ，然后调用
If the view you want to capture is in /WEB-INF/views/my.jsp, then call
request.getRequestDispatcher("/WEB-INF/views/my.jsp").include(request, myResponse);
在这里myResponse或者是一个 HttpServletResponseWrapper 您已经创建，或弹簧 MockHttpServletResponse 。在后一种情况下，可以得到从getContentAsString（）输出呈现
where myResponse is either a HttpServletResponseWrapper that you've created, or a Spring MockHttpServletResponse. In the latter case you can get the rendered output from getContentAsString().
下面
我遇到了另一个SO question各地捕获的servlet反应，有一些指向HttpServletResponseWrappers，你可以使用。
I ran into another SO question around capturing servlet responses that had some pointers to HttpServletResponseWrappers that you can use.
两个实现，好看：
- DWR SwallowingHttpServletResponse
- SiteMesh的 PageResponseWrapper
- DWR SwallowingHttpServletResponse
- Sitemesh PageResponseWrapper
享受，
这篇关于Spring MVC的 - AJAX，JSON响应包含渲染JSP视图的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！