6阿贾克斯后模型控制器

6阿贾克斯后模型控制器

本文介绍了ASP.NET 5 / MVC 6阿贾克斯后模型控制器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在我的ASP.NET MVC 5 6的应用程序,我要发布使用Ajax的一些数据,我的控制器。我已经做到了这一点与ASP.NET MVC 5和我在一个空白的ASP.NET MVC 5项目测试完全相同的code和它的工作,但随着新的版本,我不能,我不知道为什么。随着Ajax调用,我可以到控制器,创建模型,但字段为空(或假布尔)。这是我的code:

In my ASP.NET 5 MVC 6 application, I want to post with Ajax some data to my controller. I already done this with ASP.NET MVC 5 and I tested the exact same code in an blank ASP.NET MVC 5 project and it worked, but with the new version I can't and I don't know why.With the Ajax call, I can go to the controller, the model is created but the fields are null (or false for the boolean). Here is my code :

的script.js:

script.js :

var data = {
            model: {
                UserName: 'Test',
                Password: 'Test',
                RememberMe: true
            }
        };

        $.ajax({
            type: "POST",
            url: "/Account/Login/",
            data: JSON.stringify(data),
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            success: function (msg) {
                // Do something interesting here.
            }
        });

AccountController.cs:

AccountController.cs :

[HttpPost]
    public JsonResult Login(LoginViewModel model)
    {
        if (ModelState.IsValid)
        {
            //var result = await SignInManager.PasswordSignInAsync(model.UserName, model.Password, model.RememberMe, shouldLockout: false);
            //if (result.Succeeded)
            //{
            //     //return RedirectToLocal(returnUrl);
            //}

            ModelState.AddModelError("", "Identifiant ou mot de passe invalide");
            return Json("error-model-wrong");
        }

        // If we got this far, something failed, redisplay form
        return Json("error-mode-not-valid");
    }

LoginViewModel.cs:

LoginViewModel.cs :

public class LoginViewModel
{
    [Required]
    [Display(Name = "UserName")]
    [EmailAddress]
    public string UserName { get; set; }

    [Required]
    [DataType(DataType.Password)]
    [Display(Name = "Password")]
    public string Password { get; set; }

    [Display(Name = "Remember me?")]
    public bool RememberMe { get; set; }
}

任何想法?谢谢

Any ideas ?Thanks

推荐答案

您需要在MVC6明确使用FromBody如果您正在使用JSON

You need to explicit use FromBody on MVC6 if you are using json

public JsonResult Login([FromBody]LoginViewModel model)

修改

我觉得你混合不同的错误。我会尽力来形容你应该如何提出请求:

I think you are mixing different errors. I will try to describe how you should make the request:

内容类型的必须:应用程序/ JSON

content-type must be: application/json

您请求主体的必须 JSON格式(如JasonLind建议):

your request body must be in JSON format (as JasonLind suggested):

{
    UserName: 'Test',
    Password: 'Test',
    RememberMe: true
};

这是你应该看到检查的要求(通过镀铬调试工具F12)时,或使用一个请求检查就像小提琴手。

this is what you should see when inspecting the request (via chrome debugger tools F12) or using a request inspector like fiddler.

如果你看到一些在用户名=测试与放大器的形式;密码=测试和放大器;了rememberMe = TRUE ,那么你就错了,这是形式的格式

If you see something in the form of UserName=Test&Password=Test&RememberMe=true then you are doing it wrong, that's form format.

您不需要模式变量。如果你看到你的要求有一个包装,那么你应该将其删除。

you don't need the model variable. if you see your request with a "wrapper" then you should remove it.

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08-11 03:49