手动渲染的ModelAndView？

问题描述

我需要渲染的ModelAndView在我的控制器手动才能把它里面的JSON对象。如果我通过了整个ModelAndView对象为以JSON我得到没有发现串行器类javassistlazyinitializer异常，因为杰克逊不能LAZY对象正常工作。谢谢

解决方案

 公共类JSONView实现查看{
    / **
     *记录仪这一类
     * /
    私有静态最后记录器记录器= Logger.getLogger（JSONView.class）;

    私人字符串的contentType =应用/ JSON;

    公共无效渲染（地图，HttpServletRequest的请求，HttpServletResponse的响应）
        抛出异常{
    如果（logger.isDebugEnabled（））{
        logger.debug（渲染（地图，HttpServletRequest的，HttpServletResponse的） - 启动）;
    }

    的JSONObject的JSONObject =新的JSONObject（图）
    PrintWriter的作家= response.getWriter（）;
    writer.write（jsonObject.toString（））;

    如果（logger.isDebugEnabled（））{
        logger.debug（渲染（地图，HttpServletRequest的，HttpServletResponse的） - 端）;
    }
    }

    公共字符串的getContentType（）{
    返回的contentType;
    }

}
 

的ModelAndView returnModelAndView =新的ModelAndView（新JSONView（），型号）;

I need to render ModelAndView in my controller manually in order to put it inside JSON object. If I pass the whole ModelAndView object into to JSON I get " no serializer found for class javassistlazyinitializer" exception because jackson can't work properly with LAZY-objects.Thank you

解决方案

public class JSONView implements View {
    /**
     * Logger for this class
     */
    private static final Logger logger = Logger.getLogger(JSONView.class);

    private String contentType = "application/json";

    public void render(Map map, HttpServletRequest request, HttpServletResponse response)
        throws Exception {
    if(logger.isDebugEnabled()) {
        logger.debug("render(Map, HttpServletRequest, HttpServletResponse) - start");
    }

    JSONObject jsonObject = new JSONObject(map);
    PrintWriter writer = response.getWriter();
    writer.write(jsonObject.toString());

    if(logger.isDebugEnabled()) {
        logger.debug("render(Map, HttpServletRequest, HttpServletResponse) - end");
    }
    }

    public String getContentType() {
    return contentType;
    }

}

ModelAndView returnModelAndView = new ModelAndView(new JSONView(), model);

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