在Django中生成独特的插件

在Django中生成独特的插件

本文介绍了在Django中生成独特的插件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我已经看到了各种不同的方法来产生独特的s s声:,,,等等。



我想在保存ModelForm时创建独特的s。。如果我的模型如下所示:

  class Phone(models.Model):
user = models.ForeignKey(User)
slug = models.SlugField(max_length = 70,unique = True)
year = models.IntegerField()
model = models.ForeignKey('Model')
series = models请问这个$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ c> object具有以下值(通过提交的ModelForm):

  Phone.user = dude 
Phone.year = 2008
Phone.model = iphone
Phone.series = 4S

我希望此对象的网址显示为:

  http://www.mysite.com/phones/dude-2008- iphone-4S 

我明白我应该使用 slugify 通过信号或超越保存方法来实现这一点。但是,如果用户 dude 创建了第二个2008年iphone 4S对象,为此对象创建独特的插件的最佳方式是什么?我想要其他对象的URL看起来像:

  http://www.mysite.com/phones/dude-2008- iphone-4S-2 

  http://www.mysite.com/phones/dude-2008-iphone-4S-3 
http://www.mysite.com/phones/dude-2008- iphone-4S-4
#...等...

googling之后似乎有一些不同的方法来创建django的s o,这在尝试找出最佳实践时一直很混乱。



非常感谢有关这个问题的任何建议和澄清!

解决方案

p>最后我使用来覆盖我的模型中的电话保存方法。 py:

  def save(self,** kwargs):
slug_str =%s%s%s% s%(self.user,self.year,self.model,self.series)
unique_slugify(self,slug_str)
super(Phone,self).save()

但是感谢jpic的贡献。


I have seen a variety of different methods for generating unique slugs: Ex. 1, Ex.2, Ex. 3, Ex. 4, etc. etc.

I want to create unique slugs upon saving a ModelForm. If my models are like:

class Phone(models.Model):
    user = models.ForeignKey(User)
    slug = models.SlugField(max_length=70, unique=True)
    year = models.IntegerField()
    model = models.ForeignKey('Model')
    series = models.ForeignKey('Series')

Say that the Phone object has the following values (via submitted ModelForm):

Phone.user = dude
Phone.year = 2008
Phone.model = iphone
Phone.series = 4S

I want the url for this object to appear like:

http://www.mysite.com/phones/dude-2008-iphone-4S

I understand that I should use slugify via either signals or over-riding the save method to make this happen. But if user dude creates a second 2008 iphone 4S object, what the best way to create a unique slug for this object? I want the additional objects's url to look like:

http://www.mysite.com/phones/dude-2008-iphone-4S-2

and

http://www.mysite.com/phones/dude-2008-iphone-4S-3
http://www.mysite.com/phones/dude-2008-iphone-4S-4
#...etc ...

After googling, it seems like there are a variety of different methods for creating slugs in django, which has been confusing when trying to figure out best practices.

Thanks a lot for any advice and clarification on this issue!

解决方案

I ended up using This Django Snippet to over-ride the save method of Phone in my models.py:

def save(self, **kwargs):
    slug_str = "%s %s %s %s" % (self.user, self.year, self.model, self.series)
    unique_slugify(self, slug_str)
    super(Phone, self).save()

But thanks to jpic for the contribution.

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08-11 02:44