问题描述
1>值类型存储在堆栈中。
2>对象存储在堆上。
3>因此引用类型中的值类型也存储在堆中。
4>但我们不能单独声明值类型，即我们必须将它们包装在一个类中并创建对象来访问它们。
5>以这种方式，第一个陈述是矛盾的。
请帮助我，因为我在不同的文章中得到不同的东西，所以不能得出结论。
我尝试了什么：
我已经查看了不同的文章但不满意，因为我变得与众不同并且反应矛盾。
1> value types are stored in the stack .
2> objects are stored on the heap.
3> So the value types inside the reference types are also stored in heap.
4> But we cant declare value types independently i.e we have to wrap them up in a class and create objects to access them.
5> in this way the 1st statement is contradicted.
Please help me as i am getting different things in different articles, so cant conclude.
What I have tried:
I have looked into different articles but not satisfied as i am getting different and contradicting responses.
推荐答案
值类型存储在堆栈中。
static int x; // is this on the stack? :)
对象存储在堆中，该对象中的所有属性（甚至是值类型）都是该对象的一部分，因此它们是也在堆上。
Objects are stored in the heap and all properties in that object (even value types) are a part of that object so they are also on the heap.
class Foo
{
int x = 42;
string s = "Bar";
}
和该类型的实例：
and an instance of that type:
Foo f = new Foo();
f 存储数据的地址对于该实例 - 例如： 0x1234567 。该数据可能类似于：
f stores the address of the data for that instance - eg: 0x1234567. That data might look something like:
// i:
0x1234567: 0
0x1234568: 0
0x1234569: 0
0x1234570: 42
// Address of s:
0x1234571: 11
0x1234572: 173
0x1234573: 240
0x1234574: 13
i 的数据以内联方式存储： 42 。但 s 的数据存储在其他地方，地址 0x0BADF00D ：
The data for i is stored inline: 42. But the data for s is stored somewhere else, at address 0x0BADF00D:
0x0BADF009: 0 // Length
0x0BADF00A: 0
0x0BADF00B: 0
0x0BADF00C: 3
0x0BADF00D: 66 // "B"
0x0BADF00E: 97 // "a"
0x0BADF00F: 114 // "r"
当然，这会忽略 []，其存储方式与参考类型相同。
更多轻读：:)
[]
[]
[]
Of course, this ignores the concept of "boxed" value types[^], which are stored in the same way as reference types.
Some more light reading: :)
The Truth About Value Types – Fabulous Adventures In Coding[^]
Debunking another myth about value types – Fabulous Adventures In Coding[^]
Six important .NET concepts: Stack, heap, value types, reference types, boxing, and unboxing[^]
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