问题描述
我正在尝试执行一个为参数获取文件名的shell脚本.
I am trying to execute a shell script that gets for an argument a file name.
如果我去终端并输入完整的PATH，我可以做到.
I can do it if I go to the terminal and type the full PATH.
但是我试图使它更加用户友好，所以我想做的是从文件管理器或nautilus发送参数(完整路径).
But I am trying to make this more user friendly so I what I want to do is to send the argument (complete path) from the file manager or nautilus.
有可能吗?
推荐答案
好吧，我将分享一种我认为可行的方法.
Ok I am going to share a way I found that works.
我要做的就是将路径作为参数传递，而不在命令行中键入.使其变得用户友好.
All I was trying to do was to pass a path as an argument, without typing it on the command line. to make it user friendly.
因此，我使用Zenity工具(文件选择)浏览文件管理器并选择文件.
So I use a zenity tool, file selection, to browse through the file manager and select the file.
./script.sh $(zenity --file-selection)
看，现在我正在传递所选文件的路径.
See, now I am passing the path of the file I selected.
如果您想尝试一下，只需在命令行中输入即可.
If you want to try this out, just type in the command line.
zenity --file-selection
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