synchronized 例子
例1,没有同步的时候运行同一个对象的同一个方法的结果:
public class TestSyn { public synchronized void showMsg() { try { for (int i = 0; i < 3; i++) { System.out.println(Thread.currentThread().getName() + ":" + i); Thread.sleep(200); } } catch (InterruptedException e) { e.printStackTrace(); } } public static void main(String[] args) { TestSyn testSyn = new TestSyn(); ExecutorService executorService = Executors.newFixedThreadPool(10); Runnable runnable = new Runnable() { @Override public void run() { testSyn.showMsg(); } }; Runnable runnable2 = new Runnable() { @Override public void run() { testSyn.showMsg(); } }; executorService.execute(runnable); executorService.execute(runnable2); executorService.shutdown(); } }
结果:
可以看到,是同时在执行一个方法里面的内容,没有进行同步
例2,当我们其它不变,只是在方法上加synchronized后:
public class TestSyn { public synchronized void showMsg() { try { for (int i = 0; i < 3; i++) { System.out.println(Thread.currentThread().getName() + ":" + i); Thread.sleep(200); } } catch (InterruptedException e) { e.printStackTrace(); } } }
结果:
可以看到是一个方法执行完后再执行下一次,已经进行了同步
例3,我们在添加另外一个synchronized后观察运行结果:
public class TestSyn { public synchronized void showMsg() { try { for (int i = 0; i < 3; i++) { System.out.println(Thread.currentThread().getName() + ":" + i); Thread.sleep(200); } } catch (InterruptedException e) { e.printStackTrace(); } } public synchronized void showMsg2() { try { for (int i = 0; i < 3; i++) { System.out.println(Thread.currentThread().getName() + ":" + i); Thread.sleep(200); } } catch (InterruptedException e) { e.printStackTrace(); } } public static void main(String[] args) { TestSyn testSyn = new TestSyn(); ExecutorService executorService = Executors.newFixedThreadPool(10); Runnable runnable = new Runnable() { @Override public void run() { testSyn.showMsg(); } }; Runnable runnable2 = new Runnable() { @Override public void run() { testSyn.showMsg2(); } }; executorService.execute(runnable); executorService.execute(runnable2); executorService.shutdown(); } }
发不同的两个方法依然进行了同步。
我们重新新建一个对象,执行相同的同步函数观察结果:
public class TestSyn { public synchronized void showMsg() { try { for (int i = 0; i < 3; i++) { System.out.println(Thread.currentThread().getName() + ":" + i); Thread.sleep(200); } } catch (InterruptedException e) { e.printStackTrace(); } } public static void main(String[] args) { TestSyn testSyn = new TestSyn(); TestSyn testSyn2 = new TestSyn(); ExecutorService executorService = Executors.newFixedThreadPool(10); Runnable runnable = new Runnable() { @Override public void run() { testSyn.showMsg(); } }; Runnable runnable2 = new Runnable() { @Override public void run() { testSyn2.showMsg(); } }; executorService.execute(runnable); executorService.execute(runnable2); executorService.shutdown(); } }
发现不同对象的同一个方法没有进行同步
例4,我们换成一个static方法添加synchronized后:
public class TestSyn { public synchronized void showMsg() { try { for (int i = 0; i < 3; i++) { System.out.println(Thread.currentThread().getName() + ":" + i); Thread.sleep(200); } } catch (InterruptedException e) { e.printStackTrace(); } } public synchronized static void showMsg2() { try { for (int i = 0; i < 3; i++) { System.out.println(Thread.currentThread().getName() + ":" + i); Thread.sleep(200); } } catch (InterruptedException e) { e.printStackTrace(); } } public static void main(String[] args) { TestSyn testSyn = new TestSyn(); ExecutorService executorService = Executors.newFixedThreadPool(10); Runnable runnable = new Runnable() { @Override public void run() { testSyn.showMsg(); } }; Runnable runnable2 = new Runnable() { @Override public void run() { TestSyn.showMsg2(); } }; executorService.execute(runnable); executorService.execute(runnable2); executorService.shutdown(); } }
发现又没有进行同步了。
结论:
1.某个对象实例内,synchronized aMethod(){}关键字可以防止多个线程访问对象的synchronized方法(如果一个对象有多个synchronized方法,只要一个线程访问了其中的一个synchronized方法,其它线程不能同时访问这个对象中任何一个synchronized方法)。这时,不同的对象实例的synchronized方法是不相干扰的。也就是说,其它线程照样可以同时访问相同类的另一个对象实例中的synchronized方法
2.是某个类的范围,synchronized static aStaticMethod{}防止多个线程同时访问这个类中的synchronized static 方法。它可以对类的所有对象实例起作用
3.如果同一对象两个synchronized方法一个是非static方法和static方法,是不相干扰的
4.synchronized关键字是不能继承的,也就是说,基类的方法synchronized f(){} 在继承类中并不自动是synchronized f(){},而是变成了f(){}。继承类需要你显式的指定它的某个方法为synchronized方法