问题描述
我已经成功创建了一个表单，提交并将用户添加到mysql数据库，并使用除了检查用户名是否已经存在于数据库中之外，一切都很好...
I've successfully created a form that submits and adds users to a mysql database, and form validation with 'jQuery Validator' plugin works great for everything except checking to see if the username already exists in the database...
我刚刚花了大约8个小时阅读并试图计算找出一种使用'jQuery Validator'插件定义新方法的方法。我似乎无法理解如何检查数据库中输入的用户名或电子邮件，并使用jQuery返回它是否已经存在。
I've just spent about 8 hours reading and trying to figure out a way to define a new method with the 'jQuery Validator' plugin. I just can't seem to understand how I would go about checking the database for the entered username or email and return whether it already exists or not using jQuery.
我的代码：
<script src="../assets/js/main.js"></script>
<script src="../assets/js/ajax.js"></script>
<script src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.11.0/jquery.validate.min.js"></script>
<!-- FORM VALIDATION -->
<script type="text/javascript">
jQuery.validator.addMethod("checkExists",
function(value, element) {
//No idea what to call here
},
"Username already exists."
);
//<![CDATA[
$(window).load(function(){
$("form").validate({
rules: {
username: {minlength: 3, required: true, checkExists: true},
email: {email: true, required: true},
pass1: {minlength: 3, required: true},
pass2: {minlength: 3, required: true, equalTo: "#pass1"},
country: {required: true},
tandc: {required: true},
},
messages: {
username: {required: "You need to enter a Username."},
email: {required: "You need to enter an Email Address."},
pass1: {required: "You need to enter a Password."},
pass2: {required: "You need to enter your password again.", equalTo: "Your passwords don't match."},
country: {required: "You need to tell us where you live."},
tandc: {required: "You need to read and agree to the Terms and Conditions to use CGE."}
},
showErrors: function(errorMap, errorList) {
$.each(this.successList, function(index, value) {
return $(value).popover("hide");
});
return $.each(errorList, function(index, value) {
var _popover;
console.log(value.message);
_popover = $(value.element).popover({
trigger: "manual",
placement: "right",
content: value.message,
template: "<div class=\"popover\"><div class=\"arrow\"></div><div class=\"popover-inner\"><div class=\"popover-content\"><p></p></div></div></div>"
});
_popover.data("popover").options.content = value.message;
return $(value.element).popover("show");
});
}
});
});//]]>
</script>
如果有人聪明可以请修改我的代码以告诉我应该怎么做，那就是一个很大的帮助 - 我觉得我要发疯了！
If anyone clever could please amend my code to show me how I should have done it, it would be a great help - I feel like I'm about to go crazy!
提前感谢，迫不及待地想看到解决方案： - ）
Thanks in advance, can't wait to see the solution :-)
似乎根本没有发生任何事情，我觉得我离我更近了：
Nothing seems to happen at all, I feel like I'm closer though:
当前代码：
signup.php
$(window).load(function(){
$("form").validate({
rules: {
username: {minlength: 3, required: true},
email: {email: true, required: true, remote: {url: "./validation/checkUnameEmail.php", type : "post"}},
pass1: {minlength: 3, required: true},
pass2: {minlength: 3, required: true, equalTo: "#pass1"},
country: {required: true},
tandc: {required: true}
},
checkUnameEmail.php
<?php
include_once(".../php_includes/db_conx.php");
$email = urldecode($_POST['email']);
$result = mysqli_query($db_conx, "SELECT * FROM users WHERE email = '$email' LIMIT 1;");
$num = mysqli_num_rows($result);
if($num == 0){
echo "true";
} else {
echo "E-Mail-Adresse schon registriert.";
}
mysqli_close($db_conx);
?>
* db_conx.php *
*db_conx.php*
<?php
$db_conx = mysqli_connect("localhost", "root", "root", "membership");
//Evlauate the connection
if (mysqli_connect_errno()){
echo mysqli_connect_error();
exit();
}
?>
推荐答案
$.validator.addMethod("checkExists", function(value, element)
{
var inputElem = $('#register-form :input[name="email"]'),
data = { "emails" : inputElem.val() },
eReport = ''; //error report
$.ajax(
{
type: "POST",
url: validateEmail.php,
dataType: "json",
data: data,
success: function(returnData)
{
if (returnData!== 'true')
{
return '<p>This email address is already registered.</p>';
}
else
{
return true;
}
},
error: function(xhr, textStatus, errorThrown)
{
alert('ajax loading error... ... '+url + query);
return false;
}
});
}, '');
OR
您可以使用远程方法来进行远程检查：
You can use the remote method instead which allows you to do remote checks: http://docs.jquery.com/Plugins/Validation/Methods/remote
例如。
$("#yourFormId").validate({
rules: {
email: {
required: true,
email: true,
remote: {
url: "checkUnameEmail.php",
type: "post"
}
}
},
messages: {
email: {
required: "Please Enter Email!",
email: "This is not a valid email!",
remote: "Email already in use!"
}
}
});
checkUnameEmail.php //例如。
checkUnameEmail.php //Eg.
<?php
$registeredEmail = array('[email protected]', '[email protected]', '[email protected]', '[email protected]', '[email protected]');
$requestedEmail = $_REQUEST['email'];
if( in_array($requestedEmail, $registeredEmail) ){
echo 'false';
}
else{
echo 'true';
}
?>
这篇关于jQuery Validator插件 - 检查mysql数据库中的现有用户名/电子邮件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！