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问题描述

每当我使用除.find之外的任何其他内容(params [:] id],错误未定义的方法`model_name'为ActiveRecord :: Relation:Class



我的代码在

Controller:

  def edit 
@office = Office.where(id =?AND company_id =?, params [:id],@ company.id)
end

查看:

 <%= simple_form_for @office,:url => settings_office_path,:html => {:class =>office_form } do | f |%> 
< h1>编辑<%= @ office.office_name%>详情< / h1>
<%= render:partial =>'form' :locals => {:f => f}%>
<%end%>

我输出了@office的类,它是ActiveRecord :: Relation。如果我只是使用

  @ office = Office.find(params [:id])

输出是Office。



我认为这是问题,但不知道如何解决它。任何想法?

解决方案

表单期望一个记录位于 @office 实例变量,其中 - 方法不会返回单个记录,而是返回一个关系,一次查询就可以是多个记录。



正确的方法是:

  @office = Office.where(:company_id => @或者更好,如果你有更好的选择,或者更好,如果你有更好的选择,定义关系:

  @office = @ company.offices.find(params [:id])

code>


I am trying to add some more conditional logic to my edit action by passing params into a where.

Whenever I use anything other than .find(params[:id], the error undefined method `model_name' for ActiveRecord::Relation:Class

My code is below

Controller:

def edit
   @office = Office.where("id = ? AND company_id = ?", params[:id], @company.id )
end

View:

<%= simple_form_for @office, :url => settings_office_path, :html => { :class => "office_form" } do |f| %>
  <h1>Edit <%= @office.office_name %> Details</h1>
  <%= render :partial => 'form', :locals => { :f => f } %>
<% end %>

I outputted the class for @office which is ActiveRecord::Relation. If I just use

@office = Office.find(params[:id])

the output is Office.

I think this is the problem but don't know how to fix it. Any ideas?

解决方案

The form expects a single record to be in the @office instance variable, the where-method doesn't return a single record but a relation, which can be multiple records, once queried.

The correct way is:

@office = Office.where(:company_id => @company.id).find(params[:id])

Or even better, if you've defined the relation:

@office = @company.offices.find(params[:id])

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09-05 01:43