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问题描述

我正在构建一个Tinder风格的应用程序,用户可以在其中滑动事件.

I'm building a Tinder style app where users can swipe through events.

当前,我有一个后台作业,每当用户滑动事件时,都会触发该作业.随着用户每分钟浏览20个事件,我正在创建大量的后台作业:

Currently, I have a background job that is being fired any time a user swipes an event. With users swiping through 20 events per minute, I'm creating a ton of background jobs:

worker.rb

worker.rb

class Worker
  include Sidekiq::Worker

  def perform(user_id, newly_voted_event_id)
    user = User.find(user_id)
    event = Event.find(newly_voted_event_id)
    events_to_rerank = event.similar.unvoted(user_id)
    events_to_rerank.each do |e|
      e.rank(user_id)
    end
  end

end

User.rb:

def recalculate_similar_events(event_id)
    CalculateRelevantEventRankingsForUser.perform_async(self.id, event_id)
  end

我想做的是每位用户每5分钟最多运行一次后台作业.因此,我将使用sidekiq-debounce将我的后台作业更改为:

What I would like to do is run a maximum of one background job every 5 minutes per user. So I will use sidekiq-debounce change my background job to:

def recalculate_similar_events(event_id)
    CalculateRelevantEventRankingsForUser.perform_in(5.minutes, self.id, event_id)
  end

我对宝石的作用感到困惑.它会在5分钟内自动将所有作业作为一个作业执行,还是只是在每5分钟窗口中执行第一个作业?

I'm confused about what the gem does. Does it automatically execute all the jobs as one job in 5 minutes or does it just execute the first job in each 5 minute window?

推荐答案

和以往一样,如果您不确定找出最简单的方法就是查看gem代码:

As always in questions like this one if you not sure simplest way to figure out is to look into gem code:

    # Reschedule the old job to when this new job is scheduled for
    # Or yield if there isn't one scheduled yet
    jid = scheduled_jid ? reschedule(scheduled_jid, @msg['at']) : yield

因此,当您要求进行另一次运行时,如果一项工作已经在这里,则会将其重新安排为5分钟后.

so if one job is already here when you call for another run, it'll be rescheduled to 5 minutes later.

更新:从评论看来,您正在寻找 sidekiq-rate-limiter 不会反跳.

Update:As it seems from comments you looking for sidekiq-rate-limiter not debounce.

这篇关于轨道与Sidekiq:对反跳感到困惑的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-07 07:23