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问题描述
我正在尝试在 Rust 中实现八叉树.Octree 是一个泛型的类型,有一个约束,它应该实现一个泛型特征:
I'm trying to implement an Octree in Rust. The Octree is generic over a type with a constraint that it should implement a generic trait:
pub trait Generable<U> {
fn generate_children(&self, data: &U) -> Vec<Option<Self>>;
}
pub enum Octree<T, U>
where
T: Generable<U>,
{
Node {
data: T,
children: Vec<Box<Octree<T, U>>>,
},
Empty,
Uninitialized,
}
这会产生一个错误:
error[E0392]: parameter `U` is never used
--> src/main.rs:5:20
|
5 | pub enum Octree<T, U>
| ^ unused type parameter
|
= help: consider removing `U` or using a marker such as `std::marker::PhantomData`
从签名中删除 U
会导致未声明的类型名称 'U'".
Removing the U
from the signature results in "undeclared type name 'U'".
我做错了什么还是一个错误?如何正确执行此操作?
Am I doing something wrong or is it a bug? How to do this properly?
推荐答案
我不相信你在这里想要另一个泛型,你想要关联类型:
I don't believe you want another generic here, you want an associated type:
pub trait Generable {
type From;
fn generate_children(&self, data: &Self::From) -> Vec<Option<Self>>
where
Self: Sized;
}
pub enum Octree<T>
where
T: Generable,
{
Node {
data: T,
children: Vec<Box<Octree<T>>>,
},
Empty,
Uninitialized,
}
fn main() {}
顺便说一句,Vec>
可能是间接的一级额外 - 你可以只使用 Vec>代码>.
As an aside, Vec<Box<Octree<T>>>
is probably one level extra of indirection — you can just use Vec<Octree<T>>
.
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