打开另一个应用程序的系统菜单

问题描述

我有一个WPF任务栏一样，我很开心开发应用程序，我希望能够打开系统菜单的应用程序（即在我的自定义任务栏），我用鼠标右键单击，保留任何自定义菜单的应用程序可能会创建（即谷歌浏览器）。我有以下的代码，对于一个没有国界的窗口程序，我以前所作的作品，但它似乎没有工作，我想知道为什么吗？和什么我需要做的就是它的工作？

I have a WPF TaskBar like application that i am developing for fun and i want to be able to open the System Menu for the application (that is in my custom taskbar) that i right click on, preserving any custom menu that the app might create (i.e. Google Chrome). I have the following code that works for a borderless window app i made previously, but it doesn't seem to work and i am wondering why? And what do i need to do to get it to work?

    	public static void ShowContextMenu(IntPtr hWnd)
	{
		SetForegroundWindow(hWnd);
		IntPtr wMenu = GetSystemMenu(hWnd, false);
		// Display the menu
		uint command = TrackPopupMenuEx(wMenu,
			TPM.LEFTBUTTON | TPM.RETURNCMD, 0, 0, hWnd, IntPtr.Zero);
		if (command == 0)
			return;

		PostMessage(hWnd, WM.SYSCOMMAND, new IntPtr(command), IntPtr.Zero);
	}

提示：看来TrackPopupMenuEx（...）值为立即返回0，而不是等待响应...

Tip: It appears that TrackPopupMenuEx(...) returns immediately with the value of 0, instead of waiting for a response...

推荐答案

这似乎有一个问题，与给予TrackPopupMenuEx所有者窗口句柄在菜单的......相反，我用我的WPF窗口的句柄，然后张贴的消息时，我用了菜单的主人......似乎有点怪我，但它的作品！

It appears there is an issue with giving TrackPopupMenuEx the owner window handle of the Menu... instead i used the handle of my wpf window and then when posting the message, i used the Menu's owner... seems a bit strange to me but it works!

    	public static void ShowContextMenu(IntPtr hAppWnd, Window taskBar, System.Windows.Point pt)
	{
		WindowInteropHelper helper = new WindowInteropHelper(taskBar);
		IntPtr callingTaskBarWindow = helper.Handle;
		IntPtr wMenu = GetSystemMenu(hAppWnd, false);
		// Display the menu
		uint command = TrackPopupMenuEx(wMenu,
			TPM.LEFTBUTTON | TPM.RETURNCMD, (int) pt.X, (int) pt.Y, callingTaskBarWindow, IntPtr.Zero);
		if (command == 0)
			return;

		PostMessage(hAppWnd, WM.SYSCOMMAND, new IntPtr(command), IntPtr.Zero);
	}

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