问题描述
我实例化以下列表：
I instantiate the following list:
// I am just revising generics again and the following is just cursory code!
List<? super Integer> someList = new ArrayList<Object>();
someList.add(new Object());
以上行不通。我收到一个编译器错误。但是，以下工作：
The above will not work. I get a compiler error. However, the following works:
List<? super Integer> someList = new ArrayList<Object>();
someList.add(11);
我知道您可以将对象添加到包含无界通配符，不是一个有界的通配符。
I am aware that you can add objects to a collection which contains an unbounded wildcard, not a bounded wildcard.
然而，为什么上述不起作用？
一个Object是一个Integer的超类型，为什么我不能添加它？
However, why does the above not work?An Object is a supertype of an Integer, so why can't I add it?
推荐答案
它是一个超类型Integer的列表，并不是列表可以包含任何超类型的Integer。换句话说，对于编译器来说，它可以是 List< Integer> ，a List< Number> List< Object> ，但它不知道哪个，所以你不能在List中添加任何东西。唯一可以安全添加的是Integer，因为它保证了List可以容纳的任何类型的子类型。
That declares that it's a list of something that's a supertype of Integer, not that the list can contain anything that's a supertype of Integer. In other words, to the compiler, it could be a List<Integer>, a List<Number> or a List<Object>, but it doesn't know which, so you can't add just anything to the List. The only thing you can safely add is an Integer, since that's guaranteed to be a subtype of any type the List could potentially hold.
换句话说，？代表一个类型，而不是任何类型。这是一个非显而易见但重要的区别。
In other words, the ? represents one type, not any type. It's a non-obvious but important distinction.
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