如何基于每个四个逗号将字符串拆分为数组?

问题描述

所以我正尝试根据逗号数量将字符串拆分为数组，该怎么办?说我的弦是这样的；

so I'm trying to split a string into an array based on the amount of commas, how do I do that? Say my string is as such;

var string = "abc, def, ghi, jkl, mno, pqr, stu, vwx, yza";

我如何分割它以便它返回；

How can i split it so that it returns;

var array = ["abc, def, ghi, jkl,", "mno, pqr, stu, vwx,", "yza"]

这甚至有可能吗?

现在我正在使用var array = string.split(', ');

但是这会基于每个逗号将字符串添加到数组中.

But this adds the strings into the array based on every single comma.

任何帮助将不胜感激！

Any help would be appreciated!

推荐答案

我将使用.match而不是split-匹配(非逗号，后跟逗号或字符串结尾)4次:

I'd use .match instead of split - match (non commas, followed by a comma or the end of the string) 4 times:

var string = "abc, def, ghi, jkl, mno, pqr, stu, vwx, yza";
const result = string.match(/(?:[^,]+(?:,|$)){1,4}/g);
console.log(result);

• (?:[^,]+(?:,|$)){1,4}-重复1至4次:
  • [^,]+-非逗号字符
  • (?:,|$)-逗号或字符串的结尾
  • (?:[^,]+(?:,|$)){1,4} - Repeat, 1 to 4 times:
    • [^,]+ - Non comma characters
    • (?:,|$) - Either a comma, or the end of the string

    如果要确保第一个字符不是空格，请在开头搜索\S(非空格字符):

    If you want to make sure the first character is not whitespace, lookahead for \S (a non-whitespace character) at the beginning:

    var string = "abc, def, ghi, jkl, mno, pqr, stu, vwx, yza";
    const result = string.match(/(?=\S)(?:[^,]+(?:,|$)){1,4}/g);
    console.log(result);

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