本文介绍了保存日志 - SimpleHTTPServer的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何保存控制台的输出,例如
How can I save the output from the console like
192.168.1.1 - - [18/Aug/2014 12:05:59] 代码 404,消息文件未找到"
"192.168.1.1 - - [18/Aug/2014 12:05:59] code 404, message File not found"
到一个文件?
代码如下:
import SimpleHTTPServer
import SocketServer
PORT = 1548
Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
httpd = SocketServer.TCPServer(("", PORT), Handler)
print "serving at port", PORT
httpd.serve_forever()
推荐答案
BaseHTTPRequestHandler.log_message()
通过写入 sys.stderr
打印所有日志消息.你有两个选择:
BaseHTTPRequestHandler.log_message()
prints all log messages by writing to sys.stderr
. You have two choices:
1) 继续使用BaseHTTPRequestHandler.log_message()
,但是改变sys.stderr
的值:
1) Continue using BaseHTTPRequestHandler.log_message()
, but change the value of sys.stderr
:
import SimpleHTTPServer
import SocketServer
PORT = 1548
Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
httpd = SocketServer.TCPServer(("", PORT), Handler)
print "serving at port", PORT
import sys
buffer = 1
sys.stderr = open('logfile.txt', 'w', buffer)
httpd.serve_forever()
2) 新建一个xxxRequestHandler
类,替换.log_message()
:
2) Create a new xxxRequestHandler
class, replacing .log_message()
:
import SimpleHTTPServer
import SocketServer
import sys
PORT = 1548
class MyHTTPHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
buffer = 1
log_file = open('logfile.txt', 'w', buffer)
def log_message(self, format, *args):
self.log_file.write("%s - - [%s] %s
" %
(self.client_address[0],
self.log_date_time_string(),
format%args))
Handler = MyHTTPHandler
httpd = SocketServer.TCPServer(("", PORT), Handler)
print "serving at port", PORT
httpd.serve_forever()
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