计划在windows中运行bash shell脚本（问题2）

问题描述

如果我的术语不正确，请恳求任何帮助，并原谅我。

从这个问题这里：

我试图运行一个.sh文件，我使用上面的问题的答案，这基本上是

1 - 将我的文件 filename.sh 与 filename.bat

filename.bat 关联如下：

  @echo off 
 
c：
 chdir c：\cygwin\bin 
 
 bash --login％* 
  

这通常适用于我的大多数* .sh文件，例如：

 ＃！/ bin / bash 
 
＃配置bash如果命令失败，脚本将退出。 
 set -e 
 
 #this是我想要复制到
的DIR DIR =$（cd$（dirname$ {BASH_SOURCE [0]} &&pwd）
 #this是我要从
复制的DIR DIR2 = / cygdrive / v /其中/ file /是
 
 #cd到dir我想将文件复制到：
 cd$ DIR
 
 #cp文件和感兴趣的子目录
 #include子目录
 cp -r$ DIR2/ *。 
 
＃这将解压缩所有.zip文件在所有子目录下。 
＃-o需要覆盖其中的所有内容
 find -iname'* .zip'-execdir unzip -o {} \; 
 
＃这将删除第1-6行和所有csv文件的最后一行
 find ./ -iname'* .csv'-exec sed -i'1,6d; $ d''{}'';'
  

所以上面的工作当我双击它。

有些实例我注意到，当我双击它们时不工作，是脚本包含如下内容：

1->

  DIR =$（cd$（dirname$ {BASH_SOURCE [0]}）& & pwd）/ PointB 
 echo $ DIR> test.txt＃不会创建text.txt文件
  

2 - >

  #this重命名目录中的文件，请参阅[here] [2] 
 for fname in Combined *。 csv; do mv$ fname$（echo$ fname| sed -r's / [0-9] {14} //'）; done 
  

但是1& 2如果我使用命令 ./ filename.sh

$ c
运行它们从cygwin运行它们我想知道是为什么上面的1和2对我来说不起作用，通过双击它们，当他们通过调用命令 ./ filename.sh ？

注意：我在Windows XP上运行cygwin

编辑：这是我说，双击它即可工作，因为cmd窗口打开并显示此内容。

FormatCSVFiles.sh是我双击的文件。

解决方案

更正：这实际上是工作。我没有改变目录之前给echo命令。所以我的一个愚蠢的错误。 tks。

Apreciate any help and excuse me if my terminology is incorrect.
building on from this question here:

i am trying to run a .sh file, and I do this by using the answer in the question above, which is basically
1 - associating my file filename.sh with the filename.bat
filename.bat looks like this:

@echo off

c:
chdir c:\cygwin\bin

bash --login %*

This generally works for most of my *.sh files with an example being this:

#!/bin/bash

# Configure bash so the script will exit if a command fails.
set -e

#this is the DIR i want to copy to
DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
#this is the DIR i want to copy from
DIR2=/cygdrive/v/where/file/is

#cd to the dir where I want to copy the files to:
cd "$DIR"

#cp files and subdirectories of interest
#include the subdirs
cp -r "$DIR2"/* .

# This will unzip all .zip files in all subdirectories under this one.
# -o is required to overwrite everything that is in there
find -iname '*.zip' -execdir unzip -o {} \;

# this will delete row 1-6 and the last row of all the csv files
find ./ -iname '*.csv' -exec sed -i '1,6d;$ d' '{}' ';'

So the above works when I double click on it.

Some instances I have noted that do not work when I double click on them, is when the script contains something like below:
1->

DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"/PointB
    echo $DIR > test.txt #the text.txt file will not be created

2->

#this renames files in a directory, see [here][2]
for fname in Combined*.csv ; do mv "$fname" "$(echo "$fname" | sed -r 's/[0-9]{14}//')" ; done

But 1 & 2 above will work if i run them from cygwin with the command ./filename.sh

What I am wondering is why is 1 and 2 above not work for me, by double clicking on them, when they do work by invoking the command ./filename.sh?

Note: I am running cygwin on windows XP

EDIT: This is what I get when I say it does not work by double clicking it in that the cmd window opens up and displays this.

FormatCSVFiles.sh is the file I am double clicking on.

解决方案

Correction: this actually works. I was not changing directory before giving the echo command. So a silly mistake by me . tks.

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