模板非类型参数

问题描述

...a constant expression (5.19) that designates the address of an object with static storage duration and external or internal linkage or a function with external or internal linkage..."

In the code shown below, I fail to understand why 'name2' and 'name3' are not allowed as non type template arguments. I am using gcc 4.7.2 on Windows.

Both 'name2' and 'name3' are names of array and hence are constant expressions. Further 'name2' is having internal linkage and 'name3' has both static and internal linkage.

template<char const *p> void f()
{

}

char name1[] = "Hi";
static char name2[]= "Hi";
const static char name3[]= "Hi";
char *name4 = "Hi";

int main()
{
    f<name1>();
    f<name2>();
    f<name3>();
    f<name4>();
}

解决方案

As @Nawaz correctly guessed, this is an implementation bug, not an esoteric corner of the standard.

Specifically, gcc seems to have trouble with it. Barring the last name4 which is against the standard, the rest of it compiles fine with clang

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