本文介绍了java:不兼容类型:推理变量T具有不兼容的边界等式约束:下界:java.util.List<>的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我尝试从流中获取一个列表,但我有一个例外。

i try to get a list from a stream but i have an exception.

这是一个带有对象列表的Movie对象。

Here is the Movie object with a list of an object.

public class Movie {

    private String example;
    private List<MovieTrans> movieTranses;

    public Movie(String example, List<MovieTrans> movieTranses){
        this.example = example;
        this.movieTranses = movieTranses;
    }
    getter and setter

这是MovieTrans:

Here is the MovieTrans:

public class MovieTrans {

    public String text;

    public MovieTrans(String text){
        this.text = text;
    }
    getter and setter

我在列表中添加元素:

List<MovieTrans> movieTransList = Arrays.asList(new MovieTrans("Appel me"), new MovieTrans("je t'appel"));
List<Movie> movies = Arrays.asList(new Movie("movie played", movieTransList));
//return a list of MovieTrans
List<MovieTrans> movieTransList1 = movies.stream().map(Movie::getMovieTranses).collect(Collectors.toList());

我有这个编译错误:

Error:(44, 95) java: incompatible types: inference variable T has incompatible bounds
    equality constraints: MovieTrans
    lower bounds: java.util.List<MovieTrans>


推荐答案

地图打电话

movies.stream().map(Movie::getMovieTranses)

Stream< Movie> 转换为 Stream< ;列出< MovieTrans>> ,您可以将其收集到列表< List< MovieTrans>> 中,而不是列表< MovieTrans>

converts a Stream<Movie> to a Stream<List<MovieTrans>>, which you can collect into a List<List<MovieTrans>>, not a List<MovieTrans>.

要获得单个列表< MovieTrans> ,使用 flatMap

List<MovieTrans> movieTransList1 =
    movies.stream()
          .flatMap(m -> m.getMovieTranses().stream())
          .collect(Collectors.toList());

这篇关于java:不兼容类型:推理变量T具有不兼容的边界等式约束:下界:java.util.List&lt;&gt;的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-06 14:05