问题描述
我相信我可以在listOfPricedObjects上使用一个流操作:
I believe I can do next using one stream operation on listOfPricedObjects:
List<BigDecimal> myList = new ArrayList();
myList = listOfPricedObjects.stream().map(PricedObject::getPrice).collect(Collectors.toList());
BigDecimal sum = listOfPricedObjects.stream().map(PricedObject::getPrice).reduce(BigDecimal.ZERO, BigDecimal::add)
我如何使用流一次性填充myList的价格和计算价格的总和?
感谢
How I can fill myList with prices and calculate sum of prices using stream one time?Thanks
UPD:结果我需要myList填充价格和和变量sum。
UPD: As the result I need myList filled with prices and sum variable with sum. But not with usding stream() twice for that.
推荐答案
您可以使用 peek
并添加到新的列表
同时应用缩减
You can use peek
and add to a new list
while applying the reduction
List<BigDecimal> newList = new ArrayList<>();
BigDecimal sum = list.stream()
.map(PricedObject::getPrice)
.peek(newList::add)
.reduce(BigDecimal.ZERO, BigDecimal::add);
请参考Tunaki的回答,如果你有兴趣使用 parallelStream
与非并发收集,这是有道理的,因为sum作为一个尴尬的并行任务。
Please look at Tunaki answer if you interested in using a parallelStream
with a non concurrent collection which makes sense since sum as an embarrassingly parallel task.
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