问题描述
我想创建一个类似于 GitHub 处理删除存储库的方式的验证器.要确认删除,我需要输入回购名称.这里我想通过输入实体属性名称"来确认删除.我需要将名称传递给约束或以某种方式访问它,我该怎么做?
I want to create a validator similar to the way GitHub handles deleting repositories. To confirm the delete, I need to enter the repo name. Here I want to confirm delete by entering the entity property "name". I will either need to pass the name to the constraint or access it in some way, how do I do that?
推荐答案
你确实可以使用验证器约束来做到这一点:
you could indeed use a validator constraint to do that:
1:创建删除表单(直接或使用类型):
return $this->createFormBuilder($objectToDelete)
->add('comparisonName', 'text')
->setAttribute('validation_groups', array('delete'))
->getForm()
;
2:将公共属性 comparisonName
添加到您的实体中.(或使用代理对象),将映射到上面相应的表单字段.
2: Add a public property comparisonName
into your entity. (or use a proxy object), that will be mapped to the corresponding form field above.
3:定义一个类级别,回调验证器约束来比较两个值:
/**
* @Assert\Callback(methods={"isComparisonNameValid"}, groups={"delete"})
*/
class Entity
{
public $comparisonName;
public $name;
public function isComparisonNameValid(ExecutionContext $context)
{
if ($this->name !== $this->comparisonName) {
$propertyPath = $context->getPropertyPath() . '.comparisonName';
$context->addViolationAtPath(
$propertyPath,
'Invalid delete name', array(), null
);
}
}
}
4:在视图中显示表单:
<form action="{{ path('entity_delete', {'id': entity.id }) }}">
{{ form_rest(deleteForm) }}
<input type="hidden" name="_method value="DELETE" />
<input type="submit" value="delete" />
</form>
5:要验证删除查询是否有效,请在您的控制器中使用:
$form = $this->createDeleteForm($object);
$request = $this->getRequest();
$form->bindRequest($request);
if ($form->isValid()) {
$this->removeObject($object);
$this->getSession()->setFlash('success',
$this->getDeleteFlashMessage($object)
);
}
return $this->redirect($this->getListRoute());
这篇关于Symfony 2 中带有参数/参数的自定义验证器/约束的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!