本文介绍了根据列值连接不同的表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个表R,其中包含表P的外键.表P中有一列,告诉我表P中的记录是哪种类型.存在与表中列P.type中的可能值相关的信息.因此,如果P.type中的'C'代表一个名为C的表,如果'D'的值则代表一个名为D的表.

I have a table R which contains a foreign key of a table P. In table P there is a column, telling me of which type a record in table P is. Related to the possible values in column P.type according tables exist. So, if in P.type is 'C' it represents a table named C, if the value is 'D' it represents a table named D.

现在,我想拥有一条SELECT语句,该语句根据P.type分别为我提供来自表C或D的值.为了使其更复杂,结果中的列数/类型应有所不同.

Now I want to have a SELECT statement which gives me values from table C or D respectively, depending on P.type.To make it more complex, the number/types of columns in the result shall differ.

SELECT r.id, r.pid, p.type,
FROM R r
LEFT JOIN P p ON r.pid = p.pid
WHERE r.id = 123 LIMIT 1;

现在我有了P表的记录.根据列类型的值,我想确定要在先前查询中联接的表(C或D).如果必须连接表D,则返回的列(结果集)应保持原样,但如果必须连接表C,则应返回另一个列.因此,SELECT子句从

Now I've got the record of the P table. Depending on the value of column type I want to decide which table (C or D) I want to join in the prior query.If I have to join table D the returned columns (resultset) shall be as it is but if table C must be joined, a further column shall be returned. Hence, the SELECT clause changes from

选择r.id,r.pid,p.type FROM ...

SELECT r.id, r.pid, p.type FROM ...

选择r.id,r.pid,p.type,c.name FROM ...

SELECT r.id, r.pid, p.type, c.name FROM ...

Preudocode:

Preudocode:

SELECT r.id, r.pid, p.type(, c.name)   -- c.name my or may not be in the result depending on the joined table
FROM R r
LEFT JOIN P p ON r.pid = p.pid
if p.type = 'D' LEFT JOIN D d ON d.pid = p:pid end
if p.type = '' LEFT JOIN C c ON c.pid = p:pid end
WHERE r.id = 123 LIMIT 1;

发现可能要加入的表数量可以扩展(p.type的值可能从C和D增加到E,F,G等),我宁愿只加入一个由p.type指定的表,而不是在所有可能的表上方使用UNION.从而...由于结果中的列数可能不同,因此UNION尝试以错误代码1222结尾:

Sind it is possible that the number of possible tables to join can extend (the values of p.type may increase from C and D to E, F, G, ...) I'd prefer to only join the ONE table specified by p.type rather that using a UNION above all possible tables.Whereby...since the number of columns in the result my differ, a UNION attempt ended in an Error Code 1222:

这有可能吗?怎么办?

推荐答案

您的伪代码可以实现为:

Your pseudo-code can be implemented as:

SELECT r.id, r.pid, p.type, coalesce(d.name, c.name)
FROM R r LEFT JOIN
     P p
     ON r.pid = p.pid LEFT JOIN
     D d
     ON p.type = 'D' and d.pid = p.pid LEFT JOIN
     C c
     ON p.type = '' and c.pid = p.pid end
WHERE r.id = 123
LIMIT 1;

这将起作用,假设表CD没有匹配的多行.在这种情况下,您可能需要预先汇总结果或使用子查询.

This will work, assuming that the tables C and D don't have multiple rows that match. If that is the case, you might need to pre-aggregate the results or use subqueries.

这篇关于根据列值连接不同的表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-19 01:54