问题描述
我在基于 Angular 的网站中有一个设置可以打开和关闭下拉菜单.如果它关闭，则它不会显示在主页上.
I have a setting in my angular based website that turns a dropdown on and off. If it is off, then it does not show on the main page.
使用量角器，我需要检查开关关闭时是否不存在此元素.但是，我不应该陷入 Element Not Found Error，因为它是一组测试中的一个.我该怎么做?
With Protractor, I need to check to see if this element is not present when the switch is off. However, I should not be thrown into Element Not Found Error, as it is one test in a set of many. How should I do this?
我已经尝试过:
expect($$('.switch').count()).to.equal(0).and.notify(next);
但是我收到了一个 AssertionError ......
But I am getting an AssertionError with this...
推荐答案
通过使用我在文档中找到的东西来解决问题:
Got the thing working by using something I found in the docs:
expect(element(by.css('.switch')).isPresent()).to.become(false).and.notify(next);
也使用断言，所以它不会破坏 cucumberjs.
Also uses assertions, so it doesn't break cucumberjs.
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