问题描述
我尝试在开始的xml标记和结束的xml标记之间获取全部内容.
I try to get the whole content between an opening xml tag and it's closing counterpart.
在像下面的title这样的简单情况下获取内容很容易，但是如果使用 mixed-content ，我如何在标签之间获取全部内容是否要保留内部标签?
Getting the content in straight cases like title below is easy, but how can I get the whole content between the tags if mixed-content is used and I want to preserve the inner tags?
<?xml version="1.0" encoding="UTF-8"?>
<review>
<title>Some testing stuff</title>
<text sometimes="attribute">Some text with <extradata>data</extradata> in it.
It spans <sometag>multiple lines: <tag>one</tag>, <tag>two</tag>
or more</sometag>.</text>
</review>
我想要的是两个 text 标签之间的内容，包括任何标签:Some text with <extradata>data</extradata> in it. It spans <sometag>multiple lines: <tag>one</tag>, <tag>two</tag> or more</sometag>.
现在我使用正则表达式，但是有点混乱，我不喜欢这种方法.我倾向于基于XML解析器的解决方案.我查看了minidom，etree，lxml和BeautifulSoup，但找不到这种情况的解决方案(全部内容，包括内部标签).
For now I use regular expressions but it get's kinda messy and I don't like this approach. I lean towards a XML parser based solution. I looked over minidom, etree, lxml and BeautifulSoup but couldn't find a solution for this case (whole content, including inner tags).
推荐答案
from lxml import etree
t = etree.XML(
"""<?xml version="1.0" encoding="UTF-8"?>
<review>
<title>Some testing stuff</title>
<text>Some text with <extradata>data</extradata> in it.</text>
</review>"""
)
(t.text + ''.join(map(etree.tostring, t))).strip()
这里的诀窍是t是可迭代的，并且在迭代时会产生所有子节点.由于etree避免了文本节点，因此还需要使用t.text恢复第一个子标记之前的文本.
The trick here is that t is iterable, and when iterated, yields all child nodes. Because etree avoids text nodes, you also need to recover the text before the first child tag, with t.text.
In [50]: (t.text + ''.join(map(etree.tostring, t))).strip()
Out[50]: '<title>Some testing stuff</title>\n <text>Some text with <extradata>data</extradata> in it.</text>'
或者:
In [6]: e = t.xpath('//text')[0]
In [7]: (e.text + ''.join(map(etree.tostring, e))).strip()
Out[7]: 'Some text with <extradata>data</extradata> in it.'
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