创建一个独特的日期序列

问题描述

假设我想生成一个包含
的列的数据框，结构如下：

  2011-08-01 
 2011-08-02 
 2011-08-03 
 2011-08-04 
 ... 
  

我想知道是否可以使用 seq（）命令。

如下所示：（显然不起作用）

  seq（2011-08-01：2011-08-31）
  

使用日期和正则表达式生成此
特定格式的日期。

解决方案

正如我在评论中指出的， seq 具有日期的方法， seq.Date ：

  seq（as.Date（'2011-01-01'），as.Date（'2011-01-31'），by = 1）
 [1] 2011-01-012011-01-022011-01-032011-01-042011-01-052011-01-062011-01-072011 -01-08
 [9]2011-01-092011-01-102011-01-11 2011-01-122011-01-132011-01-142011-01-152011-01-16
 [17]2011-01-17 2011-01-182011-01-192011-01-202011-01-212011-01-222011-01-232011-01-24
 [25]2011-01-252011-01-262011-01-272011-01-282011-01-292011-01-302011 -01-31
  

Let's say that I want to generate a data frame which contains a column withis structured in the following format.

2011-08-01
2011-08-02
2011-08-03
2011-08-04
...

I want to know if it's possible to generate this data with the seq() command.

Something like the following: (obviously doesn't work)

seq(2011-08-01:2011-08-31)

Would I instead have to use toDate and regex to generate this date in thisspecific format.

解决方案

As I noted in my comment, seq has method for dates, seq.Date:

seq(as.Date('2011-01-01'),as.Date('2011-01-31'),by = 1)
 [1] "2011-01-01" "2011-01-02" "2011-01-03" "2011-01-04" "2011-01-05" "2011-01-06" "2011-01-07" "2011-01-08"
 [9] "2011-01-09" "2011-01-10" "2011-01-11" "2011-01-12" "2011-01-13" "2011-01-14" "2011-01-15" "2011-01-16"
[17] "2011-01-17" "2011-01-18" "2011-01-19" "2011-01-20" "2011-01-21" "2011-01-22" "2011-01-23" "2011-01-24"
[25] "2011-01-25" "2011-01-26" "2011-01-27" "2011-01-28" "2011-01-29" "2011-01-30" "2011-01-31"

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