将二维数组传输到二维ArrayList吗

将二维数组传输到二维ArrayList吗

本文介绍了将二维数组传输到二维ArrayList吗?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这段代码:

int[][] pattern = new int[][]{
        { 1, 1, 1, 1, 1, 1, 1 },
        { 1, 2, 0, 0, 0, 2, 1 },
        { 1, 0, 3, 0, 3, 0, 1 },
        { 1, 0, 0, 4, 0, 0, 1 },
        { 1, 0, 3, 0, 3, 0, 1 },
        { 1, 2, 0, 0, 0, 2, 1 },
        { 1, 1, 1, 1, 1, 1, 1 },
};

我需要将此2d数组放入2d ArrayList中,以便我可以通过添加行和列来移动模式来对其进行操作.例如,当我的方法要求移动2行和2列时,我将能够将模式移动到如下所示:

I need to get this 2d array into a 2d ArrayList so i can manipulate it by adding rows and columns to move the pattern around. For example when my method calls for a shift of 2 rows and 2 columns i will be able to move the pattern to something like this:

        { 0, 0, 0, 0, 0, 0, 0, 0, 0 }
        { 0, 0, 0, 0, 0, 0, 0, 0, 0 }
        { 0, 0, 1, 1, 1, 1, 1, 1, 1 },
        { 0, 0, 1, 2, 0, 0, 0, 2, 1 },
        { 0, 0, 1, 0, 3, 0, 3, 0, 1 },
        { 0, 0, 1, 0, 0, 4, 0, 0, 1 },
        { 0, 0, 1, 0, 3, 0, 3, 0, 1 },
        { 0, 0, 1, 2, 0, 0, 0, 2, 1 },
        { 0, 0, 1, 1, 1, 1, 1, 1, 1 },

我只是想将2d数组放入2d Arraylist中,因此不胜感激!

I'm just looking to get the 2d array into a 2d Arraylist any help will be greatly appreciated!

推荐答案

案例1 简短,但需要将基本类型隐式引用为引用类型(intInteger),例如Arrays.asList();

Case 1 It is short, but need to covert the primitive type to reference type (int to Integer) as needed for Arrays.asList();

Integer[][] pattern = new Integer[][]{
        { 1, 1, 1, 1, 1, 1, 1 },
        { 1, 2, 0, 0, 0, 2, 1 },
        { 1, 0, 3, 0, 3, 0, 1 },
        { 1, 0, 0, 4, 0, 0, 1 },
        { 1, 0, 3, 0, 3, 0, 1 },
        { 1, 2, 0, 0, 0, 2, 1 },
        { 1, 1, 1, 1, 1, 1, 1 },
};
List<List<Integer>> lists = new ArrayList<>();
for (Integer[] ints : pattern) {
    lists.add(Arrays.asList(ints));
}

案例2 :如果您不想将原始类型转换为引用类型:(int[][] pattern = new int[][]Integer[][] pattern = new Integer[][])

Case 2 If you don't want to covert the primitive type to reference type: (int[][] pattern = new int[][] to Integer[][] pattern = new Integer[][])

List<List<Integer>> lists = new ArrayList<>();
for (int[] ints : pattern) {
    List<Integer> list = new ArrayList<>();
    for (int i : ints) {
        list.add(i);
    }
    lists.add(list);
}

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08-06 07:06