问题描述
我正在尝试使用茧形宝石来构建嵌套表格.
I am trying to use cocoon gem to build nested forms.
我有用于Organisation,Package :: Bip和Tenor的模型.
I have models for Organisation, Package::Bip and Tenor.
关联是:
组织
has_many :bips, as: :ipable, class_name: Package::Bip
accepts_nested_attributes_for :bips, reject_if: :all_blank, allow_destroy: true
Package :: Bip(多态)
Package::Bip (polymorphic)
belongs_to :ipable, :polymorphic => true, optional: true, inverse_of: :bip
has_one :tenor, as: :tenor
accepts_nested_attributes_for :tenor, reject_if: :all_blank, allow_destroy: true
Tenor(多态)
belongs_to :tenorable, :polymorphic => true, optional: true
表格具有:
在我的组织/_form.html.erb中,我有:
In my organisations/_form.html.erb, I have:
<%= f.simple_fields_for :bips do |f| %>
<%= f.error_notification %>
<%= render 'package/bips/bip_fields', f: f %>
<% end %>
<%= link_to_add_association 'Add another intellectual property resource', f, :bips, partial: 'package/bips/bip_fields' %>
在我的bip_fields.html.erb嵌套表格中,我有:
In my bip_fields.html.erb nested form, I have:
<%# if @package_bips.tenor.blank? %>
<%= link_to_add_association 'Add timing', f, :tenor, partial: 'tenors/tenor_fields' %>
<%# end %>
<%= f.simple_fields_for :tenor do |tenor_form| %>
<%= f.error_notification %>
<%= render 'tenors/tenor_fields', f: tenor_form %>
<% end %>
JavaScript
茧文档建议添加一个js文件以将association-insertion-node指定为函数.在我的tenor_subform.js中,我有:
The cocoon docs suggest adding a js file to specify association-insertion-node as a function. In my tenor_subform.js I have:
$(document).ready(function() {
$(".add_tenor a").
data("association-insertion-method", 'append').
data("association-insertion-node", function(link){
return link.closest('.row').next('.row').find('.tenor_form')
});
});
控制器
在我的组织控制器中,我有:
In my organisation controller, I have:
def new
@organisation = Organisation.new
@organisation.bips
end
注意:我不确定是否需要在我的新操作中添加另一行来创建Organisation.bip.tenor实例.我也不确定我是否应该通过引用该男高音的Organisation.rb上的关联来添加has_one.
Note: I'm not sure if I need to add another line to my new action to create the organisation.bip.tenor instance. I'm also unsure if im supposed to add has_one through association on the organisation.rb that references the tenor.
def organisation_params
params.fetch(:organisation, {}).permit(:title, :comment,
bips_attributes: [:id, :status, :_destroy,
tenor_attributes: [:id,:commencement, :expiry, :_destroy]
],
在我的男高音控制器中,我有:
In my tenor controller, I have:
def tenor_params
params.require(:tenor).permit( :commencement, :expiry)
end
错误
我不确定是否需要向组织控制者(bip的最终父级,而bip的父级)添加男高音动作.
I am not sure if I need to add tenor actions to the organisation controller (the ultimate parent of bip which in turn is the parent of tenor).
保存所有内容并尝试使用时,出现错误消息:
When I save all of this and try it, I get an error that says:
unknown attribute 'tenor_id' for Tenor.
当我看到其他带有此错误的SO帖子时,通常是因为:id属性尚未在父类中列入白名单.我已经做到了.
When I see other SO posts with this error, its often because the :id attribute hasn't been whitelisted in the parent class. I have done that.
有人能看到我做错了吗?
Can anyone see what I've done wrong?
Tenor控制器
class TenorsController < ApplicationController
before_action :set_tenor, only: [:show, :edit, :update, :destroy]
before_action :authenticate_user!
# after_action :verify_authorized
def index
@tenors = Tenor.all
# authorize @tenors
end
def show
end
def new
@tenor = Tenor.new
# authorize @tenor
end
def edit
end
def create
@tenor = Tenor.new(tenor_params)
# authorize @tenor
respond_to do |format|
if @tenor.save
format.html { redirect_to @tenor }
format.json { render :show, status: :created, location: @tenor }
else
format.html { render :new }
format.json { render json: @tenor.errors, status: :unprocessable_entity }
end
end
end
def update
respond_to do |format|
if @tenor.update(tenor_params)
format.html { redirect_to @tenor }
format.json { render :show, status: :ok, location: @tenor }
else
format.html { render :edit }
format.json { render json: @tenor.errors, status: :unprocessable_entity }
end
end
end
def destroy
@tenor.destroy
respond_to do |format|
format.html { redirect_to action: :index }
format.json { head :no_content }
end
end
private
def set_tenor
@tenor = Tenor.find(params[:id])
# authorize @tenor
end
def tenor_params
params.require(:tenor).permit(:express_interest, :commencement, :expiry, :enduring, :repeat, :frequency)
end
end
推荐答案
您错误地声明了has_one
关系.因为您说as: :tenor
使其寻找tenor_id
.
You has_one
relation is wrongly declared. Because you say as: :tenor
makes it look for a tenor_id
.
您必须声明如下:
has_one :tenor, as: :tenorable
这篇关于Rails 5,Cocoon Gem-嵌套表格内的嵌套表格的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!