在XSLT中动态包含其他XSL文件

问题描述

我有一个小问题，有没有办法动态包含另一个xsl?例如:

<xsl:variable name="PathToWeb" select="'wewe'"/>
<xsl:include href="http://{$PathToWeb}/html/xsl/head.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/navigation.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/promo.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/3columns.xsl" />

<xsl:include href="http://{$PathToWeb}/html/xsl/footer.xsl" />

解决方案

我以不同的方式解决了这个问题，这可能对使用Java和XSLT的人有用(此解决方案特定于使用javax.xml.transform包的人). /p>

XSLT转换器工厂允许设置自定义URI解析器.假设您的XSLT看起来像

<?xml version="1.0" encoding="utf-8"?>
  <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="html" version="4.0" encoding="UTF-8"/>
    <xsl:include href="import://stackoverflow.com/xsl"/>
    ...

URI解析器的resolve方法将获得import://stackoverflow.com/xsl作为href参数. import://可以用作自定义包含的特殊"标识符方案，因此您可以检测到它并创建/返回指向必需文件的javax.xml.transform.Source.例如:

TransformerFactory tf = TransformerFactory.newInstance();
URIResolver delegate = tf.getURIResolver();
tf.setURIResolver( new CustomURIResolver( delegate ) );

然后在CustomURIResolver内:

  public Source resolve( String href, String base )
    throws TransformerException {
    Source result = null;
    URI uri = null;

    try {
      uri = new URI( href );
    }
    catch( Exception e ) {
      throw new TransformerException( e );
    }

    // The XSLT file has a URI path that allows for a file to be included
    // dynamically.
    if( "import".equalsIgnoreCase( uri.getScheme() ) &&
        "stackoverflow.com".equalsIgnoreCase( uri.getAuthority() ) ) {
      result = openTemplate();
    }
    else {
      result = getDelegate().resolve( href, base );
    }

    return result;
  }

添加openTemplate()方法，该方法包括动态确定要打开的XSL文件的逻辑.

I have a small problem, is there a way to dynamically include another xsl? For example:

<xsl:variable name="PathToWeb" select="'wewe'"/>
<xsl:include href="http://{$PathToWeb}/html/xsl/head.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/navigation.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/promo.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/3columns.xsl" />

<xsl:include href="http://{$PathToWeb}/html/xsl/footer.xsl" />

解决方案

I have solved this problem differently, might be useful for someone who works with Java and XSLT (this solution is specific to people using javax.xml.transform package).

XSLT transformer factory allows setting a custom URI resolver. Say if your XSLT looks like

<?xml version="1.0" encoding="utf-8"?>
  <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="html" version="4.0" encoding="UTF-8"/>
    <xsl:include href="import://stackoverflow.com/xsl"/>
    ...

The URI resolver's resolve method will get import://stackoverflow.com/xsl as a href parameter. import:// could serve as a "special" identifier scheme for custom includes, so you can detect it and create/return javax.xml.transform.Source which is pointing to the necessary file. For example:

TransformerFactory tf = TransformerFactory.newInstance();
URIResolver delegate = tf.getURIResolver();
tf.setURIResolver( new CustomURIResolver( delegate ) );

Then, inside CustomURIResolver:

  public Source resolve( String href, String base )
    throws TransformerException {
    Source result = null;
    URI uri = null;

    try {
      uri = new URI( href );
    }
    catch( Exception e ) {
      throw new TransformerException( e );
    }

    // The XSLT file has a URI path that allows for a file to be included
    // dynamically.
    if( "import".equalsIgnoreCase( uri.getScheme() ) &&
        "stackoverflow.com".equalsIgnoreCase( uri.getAuthority() ) ) {
      result = openTemplate();
    }
    else {
      result = getDelegate().resolve( href, base );
    }

    return result;
  }

Add an openTemplate() method that includes the logic to dynamically determine the XSL file to open.

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