为什么std :: condition_variable不能通过锁类型模板化？

问题描述

在调试模式下具有断言能力是非常有用的，因为开销相当小，互斥锁是否被锁定。查看已知选项，我选择了实现此选项由于低开销，使用 $

As can be seen, the method requires a very specific / p>

I don't understand

1. 为什么会这样？

如果意图是强制使用 std :: unique_lock ，那么为什么不能使用以下内容：

Even if the intent was to enforce the use of std::unique_lock, then why couldn't the following be used:

template<class Predicate, class Lock=std::mutex>
void wait(std::unique_lock<Lock> &lock, Predicate pred);

1. li>
   

1. how to reasonably get around this?

编辑

并进一步指出@TC，绝对正确和非常简单的解决方案是使用 <$

As explained by @Lingxi, and further pointed out by @T.C, the absolutely correct and very simple solution here is to use condition_variable_any, which was designed for stuff like this.

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