Git仅从特定文件夹合并

问题描述

我为客户端X创建了一个rails网站。我现在有一个客户端Y，他希望网站能够完成与客户端X完全相同的功能，但具有不同的外观。

我从clientXcode创建了一个git分支，并将其称为clientYcode。然后，我对视图做了所有更改，使其看起来与众不同，并且lala是具有不同皮肤的同一网站。

现在，我不明白git：我在视图，模型和控制器中对clientXcode做了很多更改;现在我想将这些更改合并到clientYcode中，排除任何视图更改。由于视图，模型和控制器在rails中都有自己的文件夹，我希望能够做到这样的事情：

  git合并client_x_code'app / controllers / *'，'app / models / *'
  

问题1：Is类似git的可能吗？如果是这样，我该怎么做？

问题2：分支是制作我的项目副本的最佳解决方案吗？

那么我发现了最简单的解决方案，我的问题...

  git checkout clientYcode 
 git checkout clientXcodeapp / controllers /
 git checkout clientXcodeapp / models /
  

这就是我想要的！

I've created a rails website for client X. I now have a client, Y, who wants a website that does the exact same thing as client X, but with a different skin.

I made a git branch from clientXcode and called it clientYcode. I then did all the changes to the views to make it look different, and lala, the same website with a different skin.

Now here's what I don't understand about git: I've made many changes to clientXcode in the views, models, and controllers; and now I want to merge those changes into clientYcode, excluding any view changes. Since views, models, and controllers each have their own folder in rails I was hoping to be able to do something like:

git merge client_x_code 'app/controllers/*', 'app/models/*'

QUESTION 1: Is something like that possible with git? If so, how would I do it?

QUESTION 2: Was branching the best solution to make a copy of my project?

解决方案

Well I found the easiest solution to my problem...

git checkout clientYcode
git checkout clientXcode "app/controllers/"
git checkout clientXcode "app/models/"

And that does what I want!

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