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问题描述

如何反转 gmtime(),在其中输入时间+日期并获得秒数?

How do you do reverse gmtime(), where you put the time + date and get the number of seconds?

我有类似'Jul 9,2009 @ 20:02:58 UTC'之类的字符串,我想获取从纪元到七月的秒数2009年9月9日。

I have strings like 'Jul 9, 2009 @ 20:02:58 UTC', and I want to get back the number of seconds between the epoch and July 9, 2009.

我尝试了 time.strftime ,但我不知道如何正确使用它,

I have tried time.strftime but I don't know how to use it properly, or if it is the correct command to use.

推荐答案

如果您来到这里是因为搜索引擎告诉您这是如何获取Unix时间戳记,请停止阅读此答案。向下滚动一个。

If you got here because a search engine told you this is how to get the Unix timestamp, stop reading this answer. Scroll down one.

如果要反转 time.gmtime(),则需要 calendar.timegm()

>>> calendar.timegm(time.gmtime())
1293581619.0

您可以将字符串转换成 time.strptime()的时间元组,它返回一个时间元组,您可以将其传递给 calendar.timegm()

You can turn your string into a time tuple with time.strptime(), which returns a time tuple that you can pass to calendar.timegm():

>>> import calendar
>>> import time
>>> calendar.timegm(time.strptime('Jul 9, 2009 @ 20:02:58 UTC', '%b %d, %Y @ %H:%M:%S UTC'))
1247169778

有关日历模块的更多信息

More information about calendar module here

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08-06 04:30