SQL Server 2008 Express Edition - 如何创建序列

问题描述

我使用的是 SQL Server 2008 Express Edition.

I'm using SQL Server 2008 Express Edition.

我想用这个代码创建一个序列:

I wanna create a sequence with this code:

CREATE SEQUENCE Postoffice_seq
    AS bigint
    START WITH 1
    INCREMENT BY 1
    MINVALUE 0
    NO MAXVALUE;

错误是

消息 343，级别 15，状态 1，第 1 行
在 CREATE、DROP 或 ALTER 语句中使用了未知的对象类型SEQUENCE".

有人可以帮我吗?

最好的问候！

推荐答案

SQL Server 2008 尚不知道序列 - 这将在 SQL Server 2012(又名Denali")中引入.

SQL Server 2008 doesn't know sequences yet - that'll be introduced in SQL Server 2012 (f.k.a. "Denali").

要获得几乎相同的结果，请改用 INT IDENTITY 列:

For pretty much the same result, use an INT IDENTITY column instead:

CREATE TABLE dbo.YourTable
  (YourID INT IDENTITY(1,1) NOT NULL PRIMARY KEY,
    ....
  )

IDENTITY 列在您向表中插入新行时由 SQL Server 自动填充.SQL Server 确保它是单调递增的，从 1 开始，递增 1(如果需要，您可以将这些设置为不同的值).

The IDENTITY column is automatically filled by SQL Server at the time you insert a new row into the table. SQL Server makes sure it's monotonically increasing, starting at 1, increasing by 1 (you can set these to different values, if needed).

基本上，在向此类表中插入行时，您必须不要在列列表中指定 IDENTITY 列以将值插入其中 - SQL Server 会自动为您执行此操作.

Basically, when inserting a row into such a table, you must not specify the IDENTITY column in your list of columns to insert values into - SQL Server will do this for you automatically.

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