问题描述
这是针对以下问题的后续问题:如何解决:无法为自动强制推断合适的寿命.
This is a follow up question to: How to fix: cannot infer an appropriate lifetime for automatic coercion.
我想知道这两种结构为何受寿命影响的方式不同.
I wonder why do these both structs differ in the way they are affected by lifetimes.
示例1
use http;
pub struct Request<'a> {
pub origin: &'a http::server::Request,
}
示例2
use http;
pub struct Response<'a, 'b> {
pub origin: &'a mut http::server::ResponseWriter<'b>,
}
它们看起来与我非常相似,除了第二个引用具有可变的引用,而第一个引用具有不变的引用.
They look pretty much similar to me except that the second one holds a mutable reference whereas the first one holds an immutable reference.
但是,对于示例2 ,我不能仅使用生存期作为参考.我也必须给出该结构的生命期.
However, for Example 2 I can't just use a lifetime for the reference. I must give a lifetime for the struct as well.
所以,我想知道结构中是否有 导致这种行为,或者确实是因为第二个示例中的那个是可变的引用.如果是这样,为什么会导致这种情况.
So, I wonder is there something inside the struct that causes such behavior or is it really because the one in the second example is a mutable reference. And if so, why exactly does that cause that.
推荐答案
&'a T
表示您引用了在整个生命周期内有效的T
对象.
&'a T
means that you have a reference to a T
object which is valid for the lifetime'a
.
T<'b>
表示T
对象,其中包含一个在其内部有效期为'b
的对象,如struct T<'b> { t: &'b U }
中一样.
T<'b>
means a T
object containing an object inside itself valid for the lifetime 'b
, as in struct T<'b> { t: &'b U }
.
&'a T<'b>
是对T<'b>
对象具有生存期'a
的引用.
&'a T<'b>
is thus a reference with lifetime 'a
to a T<'b>
object.
对于ResponseWriter
,它包含对Request
和TcpStream
的引用,而Request
不包含任何引用.
In the case of the ResponseWriter
, it contains references to the Request
and to the TcpStream
, whereas the Request
does not contain any references.
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