问题描述
我里面有很多命令的测试脚本，并会产生大量的输出，我用设置-x 或设置-v 和设置-e ，所以当发生错误的脚本将停止。然而，它仍然是相当困难的，我找到这行做了停止执行，以查找问题。
有可输出执行每个行之前的脚本的行号的方法？
或输出由生成的命令展前行数设置-x ？
或者可以处理我的脚本线位置问题的任何方法将是一个很大的帮助。
谢谢你。
I have a test script which has a lot of commands and will generate lots of output, I use set -x or set -v and set -e, so the script would stop when error occurs. However, it's still rather difficult for me to locate which line did the execution stop in order to locate the problem.Is there a method which can output the line number of the script before each line is executed?Or output the line number before the command exhibition generated by set -x?Or any method which can deal with my script line location problem would be a great help.Thanks.
推荐答案
您提到，您已经在使用 -x 。变量 PS4 表示值是命令行前打印的提示时， -x 选项设置是呼应和默认为：和空格
You mention that you're already using -x. The variable PS4 denotes the value is the prompt printed before the command line is echoed when the -x option is set and defaults to : followed by space.
您可以修改 PS4 来发出 LINENO （在脚本或shell函数当前正在执行的行号）
You can change PS4 to emit the LINENO (The line number in the script or shell function currently executing).
例如，如果你的脚本内容：
For example, if your script reads:
$ cat script
foo=10
echo ${foo}
echo $((2 + 2))
执行它因此将打印行数：
Executing it thus would print line numbers:
$ PS4='Line ${LINENO}: ' bash -x script
Line 1: foo=10
Line 2: echo 10
10
Line 3: echo 4
4
http://wiki.bash-hackers.org/scripting/debuggingtips给出了最终的 PS4 这将输出一切您可能需要追踪：
http://wiki.bash-hackers.org/scripting/debuggingtips gives the ultimate PS4 that would output everything you will possibly need for tracing:
export PS4='+(${BASH_SOURCE}:${LINENO}): ${FUNCNAME[0]:+${FUNCNAME[0]}(): }'
这篇关于如何执行bash脚本时，显示行数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！