本文介绍了C＃TCP套接字错误-10060的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有一个Windows服务充当服务器。我运行一个Windows窗体应用程序窗体localhost作为客户端。这两个程序都使用TCP套接字连接来发送/接收数据。
服务器在端口8030上侦听。程序运行正常。
I have a windows service act as a server. And I run one windows form application form localhost as a client. Both the programs use TCP socket connection to send/recieve data.Server listens on port 8030. The program works fine.
BUt当我增强了客户端程序以在特定端口上进行通信时，例如9030。服务器会生成以下异常。
BUt when I enhanced the client program to communicate on specific port let's say 9030. While getting connected to server it generates the following exception.
连接尝试失败，因为一段时间后连接方未正确响应，或者由于连接的主机而建立连接失败无法响应192.168.10.198:8030
任何建议都会受到高度赞赏。
Any suggestion will be highly appreciated.
谢谢，
Madhusmita
Thanks,Madhusmita
为了获得奖励
服务器程序代码
public partial class TestService : ServiceBase
{
Socket serverSocket = null;
public Timer timer1;
IPEndPoint ipEndPoint;
public TestService()
{
InitializeComponent();
timer1 = new Timer(10000);
timer1.Elapsed += new ElapsedEventHandler(timer1_Elapsed);
}
protected override void OnStart(string[] args)
{
EventLog.WriteEntry("Application", "Service started", EventLogEntryType.Information, 555);
try
{
ipEndPoint = new IPEndPoint(IPAddress.Any, 8030);
//Defines the kind of socket we want :TCP
serverSocket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp)
//Bind the socket to the local end point(associate the socket to local end point)
serverSocket.Bind(ipEndPoint);
//listen for incoming connection attempt
// Start listening, only allow 10 connection to queue at the same time
serverSocket.Listen(10);
timer1.Start();
}
catch (SocketException ex)
{
EventLog.WriteEntry("Application", ex.ErrorCode + "-" +ex.Message, EventLogEntryType.Error, 555);
}
catch (Exception ex)
{
EventLog.WriteEntry("Application", ex.Message, EventLogEntryType.Error, 555);
}
}
void timer1_Elapsed(object sender, ElapsedEventArgs e)
{
try
{
// The program is suspended while waiting for an incoming connection.
// This is a synchronous TCP application
Socket handler = serverSocket.Accept();
byte[] fileDetails = new byte[1500];
//Recieve the file details
handler.Receive(fileDetails);
int fileNameLength = BitConverter.ToInt32(fileDetails, 0);
string fileName = Encoding.ASCII.GetString(fileDetails, 4, fileNameLength);
int fileLength = BitConverter.ToInt32(fileDetails, 4 + fileNameLength);
FileStream fs = new FileStream(@"C:\Demo\" + fileName, FileMode.Append, FileAccess.Write);
int byteRead = 0;
while (byteRead < fileLength)
{
byte[] data = new Byte[1500];
//Recieve teh data and write to the file
int r = handler.Receive(data);
fs.Write(data, 0, r);
byteRead += r;
}
fs.Close();
EventLog.WriteEntry("Application", "File saved successfully", EventLogEntryType.SuccessAudit, 555);
EndPoint endPoint = (EndPoint)ipEndPoint;
handler.Send(Encoding.ASCII.GetBytes("Done"));
handler.Close();
}
catch (SocketException ex)
{
EventLog.WriteEntry("Application", ex.Message, EventLogEntryType.Error, 555);
}
catch (IOException ex)
{
EventLog.WriteEntry("Application", ex.Message, EventLogEntryType.Error, 555);
}
catch (Exception ex)
{
EventLog.WriteEntry("Application", ex.Message, EventLogEntryType.Error, 555);
}
}
protected override void OnStop()
{
timer1.Stop();
}
protected override void OnPause()
{
timer1.Stop();
}
protected override void OnContinue()
{
timer1.Start();
}
protected override void OnShutdown()
{
timer1.Stop();
}
}
客户程序代码
public partial class Form1 : Form
{
Socket socketClient;
IPEndPoint remoteEndPoint;
public Form1()
{
InitializeComponent();
}
private void buttonX1_Click(object sender, EventArgs e)
{
try
{
//Code to connect to server by by specifing the IP and port of the server on
//which the server application is hosted
socketClient = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
//socketClient.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReuseAddress,(int)1);
//IP address of the machine where the server program is hosted
IPAddress remoteIPAddress = IPAddress.Parse(txtXIPAddress.Text.Trim());
//Specify the specific port no thart the server listens to accept the data
int port = int.Parse(txtXPort.Text.Trim());
remoteEndPoint = new IPEndPoint(remoteIPAddress, port);
**//This two line causing the exception**
IPEndPoint endPoint = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 9030);
socketClient.Bind(endPoint);
//Establish the connection to server
socketClient.Connect(remoteEndPoint);
MessageBox.Show("Connection established. Please select a file to send.");
}
catch (SocketException ex)
{
MessageBox.Show(ex.ErrorCode.ToString() + "-" + ex.Message);
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
private void btnXBrowse_Click(object sender, EventArgs e)
{
if (socketClient != null)
{
openFileDialog1.ShowDialog();
}
else
{
MessageBox.Show("Please connect to the server first");
}
}
private void openFileDialog1_FileOk(object sender, CancelEventArgs e)
{
txtXFile.Text = openFileDialog1.FileName;
}
private void btnXTransfer_Click(object sender, EventArgs e)
{
//Check if the socket is connected to the remote host
//otherwise prompt user to get connected to the server first
if (socketClient != null && socketClient.Connected)
{
//If any file is selected then only proceed with transfer
if (!openFileDialog1.FileName.Equals(string.Empty))
{
FileStream fs = new FileStream(openFileDialog1.FileName, FileMode.Open, FileAccess.Read);
try
{
//Get the filename
string filename = Path.GetFileName(openFileDialog1.FileName);
//Covert the file name in form of byte
byte[] fileNameByte = Encoding.ASCII.GetBytes(filename);
//4- to store the filename length(as int - 4bytes)
//8- to stote the file content length(as long take 8 bytes)
int totalLength = 4 + fileNameByte.Length + 8;
//Clientdata[] reprents the data to sent to the server
//which represent the file details
byte[] clientData = new byte[totalLength];
byte[] fileNameLength = BitConverter.GetBytes(fileNameByte.Length);
byte[] fileContentLength = BitConverter.GetBytes(fs.Length);
//Copy all the data ClientData array
fileNameLength.CopyTo(clientData, 0);
fileNameByte.CopyTo(clientData, 4);
fileContentLength.CopyTo(clientData, 4 + fileNameByte.Length);
//Send the data to server
socketClient.Send(clientData);
int byteRead = 0;
int bytesToRead = (int)fs.Length;
while (bytesToRead > 0)
{
byte[] data = new Byte[1500];
byteRead = bytesToRead > 1500 ? 1500 : bytesToRead;
int n = fs.Read(data, 0, byteRead);
//Send the data to server
socketClient.Send(data);
bytesToRead -= n;
}
//Code block to get the success message from server
byte[] successmessage = new byte[4];
int msg = socketClient.Receive(successmessage);
if (Encoding.ASCII.GetString(successmessage).Equals("Done"))
{
MessageBox.Show("transfered the file successfully");
txtXFile.Text = string.Empty;
openFileDialog1.FileName = string.Empty;
}
}
catch (SocketException ex)
{
MessageBox.Show(ex.ErrorCode + "-" + ex.Message);
}
catch (IOException ex)
{
MessageBox.Show(ex.Message);
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
finally
{
fs.Close();
if (socketClient != null && socketClient.Connected)
{
socketClient.Shutdown(SocketShutdown.Both);
socketClient.Close(); ;
}
}
}
else
{
MessageBox.Show("Please select afile to transfer.");
}
}
else
{
MessageBox.Show("Please connect to the host.");
}
}
}
推荐答案
注意：您不必绑定客户端套接字的本地端-框架和/或OS将自动绑定到临时端口。实际上，如果将套接字绑定到127.0.0.1，假设连接不会引发无法访问的主机的异常，则会发生两种情况之一（我不确定是哪一种）：
Note: You don't have to bind the local end of the client's socket -- the framework and/or OS will bind to an ephemeral port automatically. In fact, if you bind the socket to 127.0.0.1, assuming connecting doesn't throw an exception about unreachable hosts, one of two things will happen (i'm not sure which):
- 客户端将尝试连接到服务器，但是由于本地端绑定到回送接口的IP，它将通过该而不是通过网络发送。 -或者-
- 客户端将通过NIC正确路由数据包，然后服务器将其获取。服务器向客户端回复确定，让我们建立此连接 ...但是由于客户端表示其地址为127.0.0.1，因此服务器将尝试连接该地址。使用其自己的环回接口，导致将127.0.0.1路由到该位置。
无论哪种方式，数据包都会以一种方式丢失机器的环回接口，客户端将永远不会看到响应。
Either way, the packets get lost in one of the machines' loopback interfaces, and the client will never see a response.
如果必须绑定到客户端中，请选择您的真实IP地址，或使用 IPAddress.Any ，像这样：
If you must bind in the client, pick your real IP address, or use IPAddress.Any, like so:
var endPoint = new IPEndPoint(IPAddress.Any, 9030);
这将绑定到给定的端口，但仍允许操作系统选择IP地址。但是127.0.0.1可能无法正常工作。
That'll bind to a given port but still let the OS choose the IP address. But 127.0.0.1 probably won't work.
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