本文介绍了时间CountDown在角度2的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我希望有一个这样的日期倒计时:
I want to have a date countdown like this:
但在角度2中,我发现这个plunkr在一个数字上加1每500毫秒:
but in angular 2, I found this plunkr that adds 1 to a number each 500 miliseconds:
这是代码:
import {Component,Input} from 'angular2/core';
import {Observable} from 'rxjs/Rx';
@Component({
selector: 'my-app',
template: `
<div>
{{message}}
</div>
`
})
export class AppComponent {
constructor() {
Observable.interval(1000)
.map((x) => x+1)
.subscribe((x) => {
this.message = x;
}):
}
}
但是我希望约会时间为1秒,直到达到0。 / p>
But I want to have a date taking one second until reach 0.
推荐答案
import { Component, NgOnInit, ElementRef, OnInit, OnDestroy } from 'angular2/core';
import { Observable, Subscription } from 'rxjs/Rx';
@Component({
selector: 'my-app',
template: `
<div>
{{message}}
</div>
`
})
export class AppComponent implements OnInit, OnDestroy {
private future: Date;
private futureString: string;
private counter$: Observable<number>;
private subscription: Subscription;
private message: string;
constructor(elm: ElementRef) {
this.futureString = elm.nativeElement.getAttribute('inputDate');
}
dhms(t) {
var days, hours, minutes, seconds;
days = Math.floor(t / 86400);
t -= days * 86400;
hours = Math.floor(t / 3600) % 24;
t -= hours * 3600;
minutes = Math.floor(t / 60) % 60;
t -= minutes * 60;
seconds = t % 60;
return [
days + 'd',
hours + 'h',
minutes + 'm',
seconds + 's'
].join(' ');
}
ngOnInit() {
this.future = new Date(this.futureString);
this.counter$ = Observable.interval(1000).map((x) => {
return Math.floor((this.future.getTime() - new Date().getTime()) / 1000);
});
this.subscription = this.counter$.subscribe((x) => this.message = this.dhms(x));
}
ngOnDestroy(): void {
this.subscription.unsubscribe();
}
}
HTML:
<my-app inputDate="January 1, 2018 12:00:00">Loading...</my-app>
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