获取访存响应数据

问题描述

我正在使用chrome devTools镜像webRequest.查看网络请求，响应中有一些我想访问的JSON数据

I'm using the chrome devTools to mirror a webRequest. Looking at the network request, there is some JSON data in the response that I want to get access to

右键单击->复制为抓取->

Right click --> Copy as fetch -->

fetch(
    "https://www.url.com/service.svc?action=FindConversation&ID=-40&AC=1",
    {
        "credentials":"include",
        "headers":{
            "accept":"*/*",
            "accept-language":"en-US,en;q=0.9",
            "action":"FindConversation",
            "content-type":"application/json; charset=UTF-8",
            "actionid":"-40",
            "unique_identifier":"062lCufCY0i5mI9NMTRUsF87XDq9ttYIonzZQjBcCOPvzoIJFOTSI6ZVNK9lMwy_iPFY2tuZzPY."
            "x-requested-with":"XMLHttpRequest"
        },
        "referrer":"https://ballard.amazon.com/OWA/",
        "referrerPolicy":"no-referrer-when-downgrade",
        "body":"contains some body data I want to manipulate",
        "method":"POST",
        "mode":"cors"
    }
).then(res => {console.log(res)})

这将打印出如下内容:

Response {type: "basic", url: "https://url/service.svc?action=FindConversation&ID=-40&AC=1", redirected: false, status: 200, ok: true, …}
body: ReadableStream
locked: false
__proto__: ReadableStream
bodyUsed: false
headers: Headers {}
ok: true
redirected: false
status: 200
statusText: "OK"
type: "basic"
url: "https://url/OWA/service.svc?action=FindConversation&ID=-40&AC=1"
__proto__: Response

当我检查刚刚发出的网络请求时，看起来它没有返回任何JSON数据，但是响应了 200 代码.那是正常的吗?

When I inspect the network request I just made, it looks like it isn't returning any JSON data, but responds with a 200 code. Is that normal?

我希望它返回JSON数据或失败.

I either expected it to return JSON data or fail.

此外，JSON响应数据在 res 中的什么位置?

Also, where would the JSON response data be in the res?

推荐答案

这是正常现象. fetch()返回一个 stream 对象，而不仅仅是主体.

This is normal behavior. fetch() returns a stream object and not just the body.

使用 res.json()提取JSON内容.对于非JSON响应，请使用 res.text()

Use res.json() to extract the JSON content.For non JSON responses, use res.text()

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