没有产生输出5 ....

本文介绍了没有产生输出5 ....的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 它正常工作并在输出文件中生成输出但是在main（）体中调用punctuatorcheck函数后它没有给出任何输出请检查它....这是代码It is working properly and generating output in output file but after calling punctuatorcheck function in main() body it is not giving any output please check it.... Here is the code#include<iostream>#include<conio.h>#include<string>#include<fstream>using namespace std;/* The grammar follwed by this analyser is : you have to give a blank to differentite between two different entities, for eginstead of writing "int c=a+b;", write it as "int c = a + b ;".To execute this program first create an "input.txt" file where the program is written or specify the path of the file which hasto be analysed, after compiling an "output.txt" file will be created where you have stored the program.*/bool keycheck(string str){string keyword[] ={"num","alpha","fnum","lnum","snum","string","struct","bool","true","false","for","while","repeat","void","main()","if","else","switch","default","case","break","continue","return","goto"};int flag=0; if(!(str[0]>='a' && str[0]<='z'))return false;for(int i=0;i<2;i++){if(str == keyword[i]){flag = 1;break;}}if(flag == 1) return true;elsereturn false;}string opcheck(string str){string AsgOperators ="="; string MDPOperators[5] ={"*","/","^"}; string A_SOperators[4]={"+","-"}; string RelOperators[10]={">=","<=","<",">","||","!="}; string NOT="!"; string OR="$"; string AND="&"; string S_C[2]={"SRT","CRT"}; int flag1=0,flag2=0,flag=0,flag3=0,flag4=0,flag5=0,flag6=0,flag7=0; for(int i=0;i<3;i++){if(str == MDPOperators[i]){flag = 1;break;}}if(flag == 1){return "MDP Operators";}else{for(int i=0;i<2;i++){if(str == A_SOperators[i]){flag1 = 1;break;}}if(flag1 == 1){return "A_S Operator";}else{for(int i=0;i<6;i++){if(str == RelOperators[i]){flag2 =1;break;}}if(flag2 == 1)return "Relational Operator";else{for(int i=0;i<2;i++){if(str == S_C[i]){flag3 =1;break;}}if(flag3 == 1)return "S_C Operators";else{if(str == "="){flag4=1;}if(flag4 == 1)return "Asg Operator";else{if(str == "!"){flag5=1;}if(flag5 == 1)return "NOT";else{if(str == "$"){flag6=1;}if(flag6 == 1)return "OR";else{if(str == "&"){flag7=1;}if(flag7 == 1){return "AND";}else{return "Error";}}}}}}}}}string Punctuatorcheck(string str){string punctuators[]={".",",","/>","{","}","(",")","]","["}; for(int i=0; i<9;i++) { if(str==punctuators[i]) {return "Punctuator"; } } return "Error"; }int ischar(char c){if((c>='A' && c<'Z') || (c>='a' && c<='z'))return 1; elsereturn 0;}int isnum(char c){if(c>='0' && c<='9')return 1; elsereturn 0;}int isnums(string str){int flag=0;for(int i = 0;i<str.length();i++)>{if(!isnum(str[i])){if(str[i] != '.'){flag=1;break;}}}if(flag == 1)return 0;elsereturn 1;}int isidentifier(string str){int flag =0; for(int i=1;i<str.length();i++)>{if(!ischar(str[i])){if(!isnum(str[i])){if(str[i] != '_'){if(str[i] == '['){i++;for(;str[i]!= ']';){if(!isnum(str[i])){flag =1;break;}i++;}}else{flag = 1;}if(flag ==1)break;}}}}return flag;}int main(){ifstream ifs("input.txt"); ofstream ofs("output.txt");int line=0,flag=0;bool check;string str="",strch,strline,strp;while(!ifs.eof()){getline(ifs,strline);line++;ofs<<"---------\n";ofs<<line<<"\n";strline = strline + " ";for(int j=0;j<strline.length();j++)>{if(strline[j] ==' ' || strline[j]=='\t'){if(str != ""){if(ischar(str[0])){check = keycheck(str);if(check){ofs<<str<<"\t --> Keywords\n";}else{flag = isidentifier(str);if(flag == 1){ofs<<str<<"\t --> Error\n";flag = 0;}else{ofs<<str<<"\t --> Identifier\n";}}if(isnum(str[0])){if(isnums(str))ofs<<str<<"\t -->Number\n";elseofs<<str<<"\t -->Error\n";}else{strch = opcheck(str);if(strch == "Error")ofs<<str<<"\t -->"<<strch<<"\n";else{strch = Punctuatorcheck(str);if(strp == "Error")ofs<<str<<"\t -->"<<strp<<"\n";elseofs<<str<<"\t -->"<<strp<<"\n";}}str="";}else{str=str+strline[j];}}}}}cout<<"output file is generated : output.txt";getch();return 0;}</fstream></string></conio.h></iostream>推荐答案if(str==punctuators[i]) will always fail as the two objects are not the same. If you wish to compare strings then you need to use one of the std::string functions. It would be simpler if you just use character comparisons, although you would need to do something about /> (not sure why that is in there).will always fail as the two objects are not the same. If you wish to compare strings then you need to use one of the std::string functions. It would be simpler if you just use character comparisons, although you would need to do something about /> (not sure why that is in there). 这篇关于没有产生输出5 ....的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！