使用CakePHP将行插入到仅包含一个IDENTITY列的表中

问题描述

在现有的帖子（下面的链接）中，我已经知道如何插入一行到Microsoft SQL Server的一个标识列。

现在我想使用CakePHP做同样的事情。但是，当我尝试以下操作时，将不会保存该记录。

  $ this  - MyModel  - >创建（）; 
 if（$ this  - > MyModel  - > save（））{
 $ this  - > log（'Record is saved'，'debug'）; 
} else {
 //始终运行以下
 $ this  - > log（'Record is not saved'，'debug'）; 
} 
  

CakePHP如何将这种记录保存到表中？ p>

MyModel的表模式如下：

  CREATE TABLE [dbo] 。[my_models]（
 [id] INT NOT NULL PRIMARY KEY IDENTITY 
）
  

不一个正确的CakePHP模型名称。 Duh！

  public function add（）{
 if（$ this-> request-> is（'post'））{
 $ this-> __ THE_CURRENT_MODEL __-> create（）; 
 if（$ this-> __ THE_CURRENT_MODEL __-> save（
 array（
'__THE_CURRENT_MODEL__'=> array（'id'=>'NULL'）
） 
））{
 $ this-> Flash-> success（__（'__current_model__已保存。 
 return $ this-> redirect（array（'action'=>'index'））; 
} else {
 $ this-> Flash->错误（__（'__current_model__无法保存，请重试。 
} 
} 
} 
  

'NULL'不是 NULL ..这将导致根本没有查询 - ID列是数字。

In an existing post (link below) I already know how to insert a row into a table with one identity column for Microsoft SQL Server.

Inserting rows into a table with one IDENTITY column only

and now I want to use CakePHP to do the same. However when I try the following, the record will not be saved.

$this -> MyModel -> create();
if ($this -> MyModel -> save()) {
    $this -> log('Record is saved', 'debug');
} else {
    // Always run the following
    $this -> log('Record is not saved', 'debug');
}

What would be the CakePHP way to save such record into the table?

The table schema for MyModel is below:

CREATE TABLE [dbo].[my_models] (
    [id] INT NOT NULL PRIMARY KEY IDENTITY
)

解决方案

For demonstration purposes the current model is written as '__THE_CURRENT_MODEL__' which is, of course, not a proper CakePHP model name. Duh!

    public function add() {
        if( $this->request->is('post') ){
            $this->__THE_CURRENT_MODEL__->create();
            if( $this->__THE_CURRENT_MODEL__->save(
                array(
                    '__THE_CURRENT_MODEL__' => array( 'id' => 'NULL' )
                )
            ) ){
                $this->Flash->success(__('The __current_model__ has been saved.'));
                return $this->redirect( array( 'action' => 'index' ) );
            }else{
                $this->Flash->error(__('The __current_model__ could not be saved. Please, try again.'));
            }
        }
    }

As you should note - the value 'NULL' is not NULL .. which would result in no query at all - the id column is numeric.

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