问题描述
有没有任何方法只提取模型的那些在cakephp v1.3中有'status = 1'的记录？
Is there any way of fetching only those records of a model which have 'status = 1' in cakephp v1.3 ?
我创建了一个名为'
我有一个名为Message的模型。我想要的是，只有那些消息被显示，包括在状态= 1的搜索结果中。 status = 0的邮件将不会显示，也不会显示在搜索结果中。
I have a model named 'Message'. What I want is that only those messages are displayed, included in search results which have 'status = 1'. Messages with a 'status = 0' won't be displayed and won't be included in search results too.
请帮助我，如果我能做到cakePHP方式，现在作为一个临时解决方案，我在每次查找消息的条件数组中使用'status = 1'。
Please help me if I can do it the cakePHP way, for now as a temporary solution I am using the 'status = 1' in the conditions array of every find of messages.
感谢
推荐答案
我会将它包含在 beforeFind（）回调方法中。您可以将其包含在每个模型的回调中（但每个模型只有一次，而不是每个查询），也可以将其应用到 AppModel
I'd include this in the beforeFind() callback method. You can include it in the callback for every model (but only once for each model--not for each query) or you can apply it to your AppModel so that all of your other models inherit it.
在 beforeFind（）回调中，您可以修改查询的结构。在这种情况下，您可以对传入的查询应用条件 array（'status'=> 1）。
In the beforeFind() callback, you can modify the structure of the query. In this case, you'd apply the condition array( 'status' => 1 ) to your incoming query. Dump the argument data structure to see what's coming in and I think it will make sense to you.
请注意，如果您选择在 AppModel ，并且必须在将来创建一个特定于 beforeFind 的模型，你需要确保你调用<$ c $ c>
Note that if you chose to do this in your AppModel and have to create a model-specific beforeFind callback in the future, you'll need to be sure that you call parent::beforeFind() in your subclass' beforeFind() method.
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