问题描述
我有一些代码，用于连接多个房间的套接字.在代码中的某个时刻，我想一次性离开所有房间，而无需断开插座.是否有可能做到这一点?如果是，那么我该怎么做?提前致谢..
I have some code where a socket is made to join multiple rooms. At some point in the code, i want to leave all the rooms at one go, without disconnecting the socket. Is it possible to do this? If yes, then how can i do this? Thanks in advance..
我正在使用 socket.IO
I am using socket.IO
推荐答案
那是可能的.您可以在不断开插座的情况下离开房间.仅当您调用 socket.disconnect() 时，套接字才会断开连接.
That's possible. You can leave rooms without disconnecting the socket. The socket disconnects only when you make a call to socket.disconnect().
为此，您必须维护每个客户加入和离开的房间列表.要离开所有房间，请遍历此列表并调用 socket.leave(roomname);
To do this you'll have to maintain a list of rooms each client joins and leaves. To leave all rooms iterate through this list and make a call to socket.leave(roomname);
这篇关于如何在Socket.IO中一次性离开套接字连接的所有房间的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！