什么是解决这个'从实例方法写入静态字段'的最佳方法'findbugs警告？

问题描述

我有一个看起来与此类似的类，并且findbugz抱怨'从实例方法写入静态字段'（ initialize（），以及 killStaticfield（））。我无法在ctor中设置静态字段。

I have a class that looks similar to this, and findbugz is complaining about the 'write to the static field from the instance method' (initialize(), and killStaticfield()). I can't set the static field in the ctor.

• 此问题的最佳解决方案是什么？



• 将staticField置于AtomicReference中是否足够？

• What is the best fix for this issue?

• Would putting staticField in an AtomicReference suffice?

 public class Something
 {
  private static SomeClass staticField = null;
  private AnotherClass aClass;
  public Something()
  {

  }

  public void initialize()
  {
    //must be ctor'd in initialize
    aClass = new AnotherClass();
    staticField = new SomeClass( aClass );
  }

  public void killStaticField()
  {
   staticField = null;
  }

  public static void getStaticField()
  {
    return staticField;
  }
}

推荐答案

尽可能接近原始设计...

Staying as close as possible to your original design...

public class Something {
  private static volatile SomeClass staticField = null;

  public Something() {
  }

  public static SomeClass getStaticField() {
    if(Something.staticField == null)
      Something.staticField = new SomeClass();;
    return Something.staticField;
  }
}

通过类名引用你的静态变量，将删除findbugz警告。
将静态变量标记为volatile，这将使参考在多线程环境中更安全。

Refer to your static variable via the class name, that will remove the findbugz warning.Mark your static variable as volatile, which will make the reference safer in a multithreaded environment.

更好的是：

public class Something {
  private static final SomeClass staticField = new SomeClass();

  public Something() {
  }

  public static SomeClass getStaticField() {
    return Something.staticField;
  }
}

这篇关于什么是解决这个'从实例方法写入静态字段'的最佳方法'findbugs警告？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！