本文介绍了如何将行转置为列的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

SOHeaderId	SODetailId
11004	        100030
11004	        100031
11004	        100032
11004	        100033
11004	        100034
11004	        100035
11004	        100036
11005           100037
11005           100038
11005           100039
11005           100040
11006           100041
11006           100042
11006           100058
11006           100078
wanted it as

SOHeaderId     SODetailId
11004           100030,100031,100032,100033,100034,100035,100036
11005           100037,100038,100039,100040
11006           100041,100042,100058,100078

WITH THE help of SQL Query only



我已经尝试过谷歌,但不能解决它。


I have already tried on google, but not able to solve it.

推荐答案

SELECT DISTINCT [SOHeaderId],
                STUFF((SELECT ',' + CAST([SODetailId] AS VARCHAR(10))
                       FROM   [TableName] t1
                       WHERE  t1.[SOHeaderId] = t2.[SOHeaderId]
                       FOR XML PATH('')), 1, 1, '')
FROM   [TableName] t2



我假设[SODetailId]的数据类型是 INT ,所以我将它转换为 VARCHAR(10)



参考文献:

1. []

2. []


I am assuming that the data type of [SODetailId] is INT, so I am casting it to VARCHAR(10).

References:
1. STUFF AND FOR XML PATH for String Concatenation[^]
2. Using FOR XML PATH and STUFF to CONCATENATE[^]


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08-05 08:55