如何修复“类型java.lang.String的值名称无法转换为JSONObject"

问题描述

我正在使用Volley在Android中发送HTTP请求，但出现此错误:

I'm am using Volley to send an HTTP request in Android and I'm getting this error:

在服务器端，我使用PHP脚本从数据库中获取值.

On the server side, I use a PHP script to get values from the database.

我的Android代码:

My Android code:

String server_url = "http://192.168.225.40/server/greetings.php";
        JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.POST, server_url,null,
                new Response.Listener<JSONObject>() {
                    @Override
                    public void onResponse(JSONObject response) {

                        try {
                            name.setText(response.getString("name"));
                            email.setText(response.getString("email"));
                        }
                        catch (JSONException e) {
                            e.printStackTrace();
                        }
                    }
                }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                if(firebaseUser!=null){
                    if(!firebaseUser.getEmail().isEmpty())
                    {
                        email.setText(firebaseUser.getEmail());}

                }

                error.printStackTrace();

            }
        }
        );
        singletonclasshttp.getInstance(getActivity()).addtorequestque(jsonObjectRequest);

我的PHP脚本:

?php
$username="root";
$password="";
$host = "localhost";
$dbname = "test";
$con = mysqli_connect($host,$username,$password,$dbname);
$sql = "select * from user where uid =1;";
$result = mysqli_query($con,$sql);
$data=array();

if(mysqli_num_rows($result)>0)
{

    $row = mysqli_fetch_assoc($result);
    echo json_encode(array("name"=>$row["name"],"email"=>$row["email"],"type"=>$row["type"]));


}


?>

我需要解析JSON并设置文本字段的值.

I need to parse the JSON and set the value for the text fields.

推荐答案

您正在获取JsonArray.您应该使用StringRequest.然后将String转换为JsonArray并从数组中获取JsonObject.

You are getting JsonArray. You should use StringRequest. Then convert String to JsonArray and get JsonObject from the array.

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