本文介绍了表[ ] 输出基数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
Table[ ]
命令通常返回一个与迭代器基数相同的列表.
The Table[ ]
command usually returns a list with the same cardinality of its iterator.
Table[i, {i,4}]
(*
->{1,2,3,4}
*)
很容易证明,可以返回一个比迭代器更大基数的列表
It is easy to show that is possible to return a list with a greater cardinality than the iterator
Table[Sequence @@ ConstantArray[1, i], {i, 2}]
(*
->{1,1,1}
*)
但是......有没有办法返回一个比迭代器LESS基数的列表?
But ... Are there ways to return a list with LESS cardinality than the iterator?
推荐答案
一个简单的例子:
Table[Sequence @@ ConstantArray[1, i - 1], {i, 2}]
Out[1] = {1}
这不需要总是返回具有较小基数的列表.例如,{i,3}
返回相等而 {i,4}
返回更多.
This need not always return a list with smaller cardinality. For e.g., {i,3}
returns equal and {i,4}
returns more.
或者更愚蠢的例子是
Table[Sequence @@ {}, {i, 2}]
但我不知道它是否重要.
but I don't know if it counts.
您也可以在 Table
Table[Sequence @@ Piecewise[{
{ConstantArray[1, i], i < 3},
{ConstantArray[2, i], 3 <= i < 5},
{{}, i >= 5}}],
{i, 20}]
Out[2] = {1, 1, 1, 2, 2, 2, 2, 2, 2, 2}
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