本文介绍了安卓：在服务器上用PHP上传图片的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
始终上传图片test.jpg放在与0KB在服务器上！
Always upload image test.jpg with 0KB on the server!
下面是图片：
所以，你可以看到我收到的服务器上。
So you can see what am i getting on the server.
我会AP preciate任何帮助或建议，我希望我会解决这个问题。
I would appreciate any help or suggesting and i hope i will solve the problem..
Android的code：
Android code:
public class Main extends Activity {
InputStream inputStream;
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
setContentView(R.layout.main);
Bitmap bitmap = BitmapFactory.decodeResource(getResources(),R.drawable.ic_launcher);
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.PNG, 90, stream); //compress to which format you want.
byte [] byte_arr = stream.toByteArray();
String image_str = Base64.encodeBytes(byte_arr);
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("image",image_str));
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://server/uploader2.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
String the_string_response = convertResponseToString(response);
Toast.makeText(this, "Response " + the_string_response, Toast.LENGTH_LONG).show();
}catch(Exception e){
Toast.makeText(this, "ERROR " + e.getMessage(), Toast.LENGTH_LONG).show();
System.out.println("Error in http connection "+e.toString());
}
}
public String convertResponseToString(HttpResponse response) throws IllegalStateException, IOException{
String res = "";
StringBuffer buffer = new StringBuffer();
inputStream = response.getEntity().getContent();
int contentLength = (int) response.getEntity().getContentLength(); //getting content length…..
Toast.makeText(this, "contentLength : " + contentLength, Toast.LENGTH_LONG).show();
if (contentLength < 0){
}
else{
byte[] data = new byte[512];
int len = 0;
try
{
while (-1 != (len = inputStream.read(data)) )
{
buffer.append(new String(data, 0, len)); //converting to string and appending to stringbuffer…..
}
}
catch (IOException e)
{
e.printStackTrace();
}
try
{
inputStream.close(); // closing the stream…..
}
catch (IOException e)
{
e.printStackTrace();
}
res = buffer.toString(); // converting stringbuffer to string…..
Toast.makeText(this, "Result : " + res, Toast.LENGTH_LONG).show();
//System.out.println("Response => " + EntityUtils.toString(response.getEntity()));
}
return res;
}}
和PHP code ...（uploader2.php）
and php code... (uploader2.php)
<?php
$base=$_REQUEST['image'];
$binary=base64_decode($base);
header('Content-Type: image/jpg; charset=utf-8');
$file = fopen('test.jpg', 'wb');
fwrite($file, $binary);
fclose($file);
echo 'Image upload complete!!, Please check your php file directory……';
echo "<img src=test.jpg>";
?>
这是什么问题？
what is the problem?
推荐答案
doFileUpload功能：
doFileUpload Function :
private void doFileUpload(){
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String exsistingFileName = "/sdcard/six.3gp";
// Is this the place are you doing something wrong.
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://192.168.1.5/upload.php";
try
{
Log.e("MediaPlayer","Inside second Method");
FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
URL url = new URL(urlString);
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e("MediaPlayer","Headers are written");
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
tv.append(inputLine);
// close streams
Log.e("MediaPlayer","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("MediaPlayer", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("MediaPlayer","Server Response"+str);
}
/*while((str = inStream.readLine()) !=null ){
}*/
inStream.close();
}
catch (IOException ioex){
Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
}
}
upload.php的
upload.php
<?php
move_uploaded_file($_FILES['uploadedfile']['tmp_name'], "./upload/".$_FILES["uploadedfile"]["name"]);
mysql_connect("localhost","root","");
mysql_select_db("chat");
if(isset($_REQUEST['msg']))
{
$a = $_REQUEST['msg'];
$sql = "INSERT INTO upload(image)VALUES('$a')";
mysql_query($sql);
}
?>
这篇关于安卓：在服务器上用PHP上传图片的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！