线串大 pandas 之间的距离

问题描述

我有一个shapefile数据集.某些道路(线)具有相同的名称，但位于不同的位置，并且没有连接.

I have a shapefile dataset. Some roads (line) have the same name but are located at different places and are not connected.

这是我的geopandas数据文件中同名公路的照片:

Here is a picture of the roads with a same name in my geopandas datafile:

我希望能够测量路段(线串)之间的距离，以便能够在距离大于阈值的情况下重命名道路，从而使每条道路都有其自己的唯一名称.

I would like to be able to measure the distance between road chunks (linestrings) to be able to rename the roads if the distance is higher than a threshold, such that each road has its own unique name.

因此，您知道如何找到线串之间的距离吗?

Hence, do you know how to find the distance between linestrings ?

推荐答案

在geopandas中，几何形状是匀称的对象.要获得任意两个匀称对象之间的距离，请使用巧妙命名的distance方法:

In geopandas, the geometries are shapely objects. To get a distance between any two shapely objects, you use the cleverly named distance method:

from shapely.geometry import Point, LineString
import geopandas

line1 = LineString([
    Point(0, 0),
    Point(0, 1),
    Point(1, 1),
    Point(1, 2),
    Point(3, 3),
    Point(5, 6),
])

line2 = LineString([
    Point(5, 3),
    Point(5, 5),
    Point(9, 5),
    Point(10, 7),
    Point(11, 8),
    Point(12, 12),
])

line3 = LineString([
    Point(9, 10),
    Point(10, 14),
    Point(11, 12),
    Point(12, 15),
])

print(line1.distance(line2))
> 0.5547001962252291

如果您有geopandas GeoSeries/GeoDataFrame，则需要对此有所了解.

If you have a geopandas GeoSeries/GeoDataFrame, you need to be a little smarter about it.

gs = geopandas.GeoSeries([line1, line2, line3])
gs.distance(gs)

返回全零，因为它在索引上将gs排列为gs，它们都是相同的几何图形.

Returns all zeros, because it lines up gs to gs on the index, which is all the same geometries.

但是:

gs.distance(gs.shift())

为您提供从第1行到第2行以及从第2行到第3行的距离:

Gives you the distances from line1 to line2, and line2 to line3:

0         NaN
1    0.554700
2    0.948683
dtype: float64

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