本文介绍了如何在Ratchet WebSockets中访问Guzzle QueryString参数?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用radchet websocket.我很难从对象变量中获取数据.

Hi I am using radchet websocket. I am getting trouble to get my data from an object variable.

请检查我的代码:

var conn = new WebSocket('ws://localhost:8080?user_id=10&receiver_id=20');
$querystring = $conn->WebSocket->request->getQuery();
print_r($querystring);

输出:

Guzzle\Http\QueryString Object
(
    [fieldSeparator:protected] => &
    [valueSeparator:protected] => =
    [urlEncode:protected] => RFC 3986
    [aggregator:protected] =>
    [data:protected] => Array
        (
            [user_id] => 10
            [receiver_id] => 20
        )
)

上面的代码我想要user_idreceiver_id,但是我无法获取.

Above code i want user_id and receiver_id but i am unable to get.

我的代码:

echo $querystring->data:protected['user_id'];
echo $querystring->data:protected['receiver_id'];

我已经回应但收到错误消息.请帮助我.

I have echoed but getting error message. Please help me.

如果我将对象转换为数组,则显示的格式不正确.见下文.

If I convert object to array it is not showing proper format. see below.

$array =  (array)  $querystring;
print_r($array);

输出:

Array
(
    [ * fieldSeparator] => &
    [ * valueSeparator] => =
    [ * urlEncode] => RFC 3986
    [ * aggregator] =>
    [ * data] => Array
        (
            [user_id] => 10
            [receiver_id] => 20
        )

)

推荐答案

Guzzle \ Http \ QueryString 扩展了 Guzzle \ Common \ Collection 应该能够使用Collection的方法:

Guzzle\Http\QueryString extends Guzzle\Common\Collection so you should be able to use Collection's methods:

$user_id = $querystring->get('user_id');
$receiver_id = $querystring->get('receiver_id');

$parameters = $querystring->toArray();
$user_id = $parameters['user_id'];
$receiver_id = $parameters['receiver_id'];

这篇关于如何在Ratchet WebSockets中访问Guzzle QueryString参数?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-05 04:53