问题描述
在调试我的代码时,我想使用列表理解.但是,当我在函数内部时,我似乎无法从调试器评估列表理解.
我使用的是 Python 3.4.
脚本内容:
$ cat test.py#!/usr/bin/python定义 foo():x = [1, 2, 3, 3, 4]打印(x)富()
交互式调试:
$ python3 -mpdb test.py>/tmp/test.py(3)()->定义 foo():(Pdb) 步骤>/tmp/test.py(8)()->富()(Pdb)- 称呼 ->/tmp/test.py(3)foo()->定义 foo():(Pdb)>/tmp/test.py(4)foo()->x = [1, 2, 3, 3, 4](Pdb)>/tmp/test.py(6)foo()->打印(x)(Pdb) p [x for _ in range(1)]*** NameError: 名称 'x' 未定义(pdb) p x[1, 2, 3, 3, 4]
为什么 x
对列表理解是未知的?我如何评估调试器的列表理解,或实现等效的行为?这是一个错误,还是调试器的某种基本限制?
在 Python 3 中,您必须在 pdb 中使用 interact
命令,然后才能访问任何由于更改而导致的非全局变量理解的实现方式.
In debugging my code, I want to use a list comprehension. However, it seems I cannot evaluate a list comprehension from the debugger when I'm inside a function.
I am using Python 3.4.
Script contents:
$ cat test.py
#!/usr/bin/python
def foo():
x = [1, 2, 3, 3, 4]
print(x)
foo()
Interactive debugging:
$ python3 -mpdb test.py
> /tmp/test.py(3)<module>()
-> def foo():
(Pdb) step
> /tmp/test.py(8)<module>()
-> foo()
(Pdb)
--Call--
> /tmp/test.py(3)foo()
-> def foo():
(Pdb)
> /tmp/test.py(4)foo()
-> x = [1, 2, 3, 3, 4]
(Pdb)
> /tmp/test.py(6)foo()
-> print(x)
(Pdb) p [x for _ in range(1)]
*** NameError: name 'x' is not defined
(Pdb) p x
[1, 2, 3, 3, 4]
Why is x
unknown to the list comprehension? How could I evaluate a list comprehension from the debugger, or achieve an equivalent behaviour? Is this a bug, or is it some sort of fundamental limitation to the debugger?
In Python 3, you have to use the interact
command in pdb before you can access any non-global variables due to a change in the way comprehensions are implemented.
>>> def foo(): [][0]
...
>>> foo()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 1, in foo
IndexError: list index out of range
>>> import pdb;pdb.pm()
> <stdin>(1)foo()
(Pdb) x = 4
(Pdb) [x for _ in range(2)]
*** NameError: name 'x' is not defined
(Pdb) interact
*interactive*
>>> [x for _ in range(2)]
[4, 4]
>>>
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